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anyanavicka [17]
3 years ago
5

A rectangle measures 4 1/2 inches by 2 3/4 inches, what is the area of the rectangle? Answer in fraction form.

Mathematics
1 answer:
makkiz [27]3 years ago
7 0
12 and 3/8 or if you want it entirely in a fraction 99/8.
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(Help please) A transformation was performed on oval A as shown in the graph. What type of transformation was performed? Does th
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-A is incorrect because the shape did not change
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URGENT!!LAST QUESTION!!!! PLS JUST TAKE A LOOK! EASY BUT I AM DUMB!!!!!! WILL GIVE BRANLIEST!!
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Answer:

x = 28

Step-by-step explanation:

If the quadrilaterals are similar, there is a proportionality among their sides:

The top side in the large figure (70) is to the top side in the small figure (10) in the same ratio as the left side (x) in the large figure is to the left side in the small figure (4). This in math terms is written as:

\frac{70}{10} =\frac{x}{4}

We can then solve for the unknown "x" by multiplying both sides by 4:

\frac{70}{10} =\frac{x}{4}\\\frac{70\,*\,4}{10} =x\\x=28

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3 years ago
If 9x x 3x+1 = 2187, what is the value of x?<br><br><br><br><br>​
Snezhnost [94]

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x = 80.96

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Here we will use the trial and error method.

  • We will try putting different values of x.
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\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
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