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3 years ago

15

The ASE certification system uses _______ testing and an evaluation of on-the-job experience to confirm that a technician meets

professional standards of excellence
A. mandatory
B. voluntary
C. specialized
D. professional

Computers and Technology

2 answers:

erma4kov [3.2K]3 years ago

7 0

MY answer would be A or C .Hope this helped

stepladder [879]3 years ago

4 0

The answer is c Hope This Helps You on your work

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What are the first and the last physical memory addressesaccessible using

Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

<u>NOTE</u>-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

1000<u>0</u> +00000 = 1000<u>0</u> (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

1000<u>0</u> +0FFFF =1FFFF (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

0FFF<u>0</u> +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

0FFF<u>0</u> +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

0001<u>0</u> +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

0001<u>0</u> +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

E000<u>0</u> +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

E000<u>0</u> +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

1002<u>0</u> +00000=10020 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

1002<u>0</u> +0FFFF =2001F (from note)

6 0

3 years ago

Choose 2 statements that correctly describe the time complexity of data structures with N data.

Softa [21]

The statements that correctly describe the time complexity of data structures with N data are:

The average time complexity of the data lookup in a hash table is O(N).
The average time complexity of inserting data into a heap is O(logN)

<h3>What is time complexity of data structures?</h3>

Time Complexity of an algorithm is known to be the depiction of the amount of time needed by the algorithm to carry out to completion.

Note that The statements that correctly describe the time complexity of data structures with N data are:

The average time complexity of the data lookup in a hash table is O(N).
The average time complexity of inserting data into a heap is O(logN)

Learn more about data from

brainly.com/question/17350816

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6 0

2 years ago

Instead of sending an entire file in one big chunk across the Internet, __________ is used which dices the file up into little

azamat

Answer:

TCP/IP

Explanation:

TCP/IP which stands for Transmission Control Protocol and Internet Protocol are network protocols which divide your message into smaller chunks or fragments known as network packets and sends them out onto the Internet. When the chunks arrive at the intended destination, TCP/IP on the receiving end reassembles the network packets into the original message.

TCP/IP are the main protocols used for sending data over the internet.

7 0

3 years ago

if the bandwidth-delay product of a channel is 500 Mbps and 1 bit takes 25 milliseconds to make the roundtrip, what is the bandw

Leona [35]

Answer:

2500 kb

Explanation:

Here, we are to calculate the bandwidth delay product

From the question, we are given that

band width = 500 Mbps

The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3

= 2500 Kbits

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How can you ensure that your web pages are compliant with a w3c standard?

miss Akunina [59]

Use a code validation tool.

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4 years ago