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Nastasia [14]
3 years ago
15

The ASE certification system uses _______ testing and an evaluation of on-the-job experience to confirm that a technician meets

professional standards of excellence
A. mandatory
B. voluntary
C. specialized
D. professional
Computers and Technology
2 answers:
erma4kov [3.2K]3 years ago
7 0
 MY answer would be A or C .Hope this helped
stepladder [879]3 years ago
4 0
The answer is c Hope This Helps You on your work
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How is it possible for the router to know whether it is supposed to send a cat photo to your laptop
kupik [55]

It is possible for the router to know whether it is supposed to send a cat photo to your laptop because  It uses the private IP address.

Router  is a  device that help to transfer data and across the internet or across the user device and the internet.

Private IP addresses are internet protocol addresses that is often  assign to user device by   router in order to a successful communicate to take place between the internet and user device.

Private IP addresses are mostly at:

•Home

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Inconclusion It is possible for the router to know whether it is supposed to send a cat photo to your laptop because  It uses the private IP address.

Learn more here:

brainly.com/question/19112414

3 0
2 years ago
In today's classrooms, computers are generally being used to
Vinvika [58]
The answer is enhance traditional instruction. Computers are often used by teachers so that the teachers may have an easier time with their visual aids. Now that we have tools like powerpoint presentations and excel files, it will be easier for the teachers to prepare 
4 0
3 years ago
Which of the following is true about binary search. A. It uses binary numbers in its algorithm B. It is slower than sequential s
trapecia [35]

Answer:

<u> A. It uses binary numbers in its algorithm</u>

Explanation:

A Binary search is a type of algorithm designed to look through <em>only </em>a sorted array of data for a particular item.

It is<em> more efficient (faster) </em>than sequential search since the algorithm doesn't have to look up the entire array of data, but simply repeatedly divide in half the section of the array that could contain the searched item.

4 0
3 years ago
Design a program for the Hollywood Movie Rating Guide, which can be installed in a kiosk in theaters. Each theater patron enters
ehidna [41]

Answer:

The program in cpp is given below.

#include <iostream>

using namespace std;

int main()

{

   //variables declared to hold sum, count and average of movie ratings

   int sum=0;

   int count=0;

   int rating;

   double avg;

   //audience is prompted to enter ratings

   do{

       std::cout << "Enter the rating (0 to 4): ";

       cin>>rating;

       if(rating>4)

           std::cout << "Invalid rating. Please enter correct rating again." << std::endl;

       if(rating>=0 && rating<=4)

       {

           sum=sum+rating;

           count++;

       }

       if(rating<0)

           break;

   }while(rating>=0);

   //average rating is computed

   avg=sum/count;

   std::cout << "The average rating for the movie is " << avg << std::endl;  

   return 0;

}

OUTPUT

Enter the rating (0 to 4): 1

Enter the rating (0 to 4): 2

Enter the rating (0 to 4): 0

Enter the rating (0 to 4): 5

Invalid rating. Please enter correct rating again.

Enter the rating (0 to 4): 1

Enter the rating (0 to 4): -1

The average rating for the movie is 1

Explanation:

1. Variables are declared to hold the rating, count of rating, sum of all ratings and average of all the user entered ratings.

2. The variables for sum and count are initialized to 0.

3. Inside do-while loop, user is prompted to enter the rating for the movie.

4. In case the user enters a rating which is out of range, the user is prompted again to enter a rating anywhere from 0 to 4.

5. The loop executes until a negative number is entered.

6. Inside the loop, the running total sum of all the valid ratings is computed and the count variable is incremented by 1 for each valid rating.

7. Outside the loop, the average is computed by dividing the total rating by count of ratings.

8. The average rating is then displayed to the console.

9. The program is written in cpp due to simplicity since all the code is written inside main().

6 0
3 years ago
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
3 years ago
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