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3 years ago

Create a quadratic equation that has complex solutions

Mathematics

1 answer:

svetoff [14.1K]3 years ago

4 0

Answer:

x^2 + x + 2 = 0.

Step-by-step explanation:

The discriminant b^2 - 4ac is < 0 for complex roots.

So we can choose appropriate values for a, b and c.

Let b = 1, a = 1 and c = 2 so b^2 - 4ac = 1 - 4*1*2 = -7.

So our equation is:

x^2 + x + 2 = 0.

You might be interested in

Jimmie graphs a quadratic function and finds that its zeros are at x=2 and x=3. Which function could Jimmie have graphed?

HACTEHA [7]

The function Jammie graphed is $x^2-5x+6=0$

Step-by-step explanation:

The zeros of quadratic function are at x=2 and x=3

We can write them as:

$x-2=0\,\,and\,\,x-3=0\\or\\(x-2)(x-3)=0$

Multiplying them

$(x-2)(x-3)=0\\x(x-3)-2(x-3)=0\\x^2-3x-2x+6=0\\x^2-5x+6=0$

So, The function Jammie graphed is $x^2-5x+6=0$

Keywords: Factors

Learn more about Factors at:

#learnwithBrainly

5 0

4 years ago

A woman put $3000 into a bank and rate of interest was 2% how much did she have a year later

irga5000 [103]

Answer:

$3060

Step-by-step explanation:

y = a ( 1+r)^t

y= 3000(1+0.02)^1

y=$3060

3 0

3 years ago

Which is the simplified form of (906)2

Over [174]

Answer:

te answer is 1812

Step-by-step explanation:

you just end up multiplying it by 2

5 0

4 years ago

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the pr

Gre4nikov [31]

Answer:

$z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5$

$z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5$

And using a calculator, excel ir the normal standard table we have that:

$P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)$

And we can calculate the probability like this: $P(-1.5 \leq Z \leq 1.5) = P(z$ Step-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(50,12)$