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sweet [91]
3 years ago
5

Create a quadratic equation that has complex solutions

Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0

Answer:

x^2 + x + 2 = 0.

Step-by-step explanation:

The discriminant b^2 - 4ac is < 0 for complex roots.

So we can choose appropriate values for a, b and c.

Let b = 1,  a = 1 and  c = 2 so b^2 - 4ac = 1 - 4*1*2 = -7.

So our equation is:

x^2 + x + 2 = 0.


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3 years ago
How to find third coordinate when given midpoint and a point?
IgorLugansk [536]
Example : 
u have an endpoint at (6,5)......ad the midpoint is (4,2)....find the other endpoint.

midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
one endpoint (6,5)....x1 = 6 and y1 = 5
other endpoint (x,y)...x2 = x and y2 = y
sub into the formula
m = (6 + x) / 2, (5 + y) / 2

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midpoint is (4,2)....so the y value will equal 2
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3 years ago
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xenn [34]

Answer:

Step-by-step explanation:

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