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sweet [91]
3 years ago
5

Create a quadratic equation that has complex solutions

Mathematics
1 answer:
svetoff [14.1K]3 years ago
4 0

Answer:

x^2 + x + 2 = 0.

Step-by-step explanation:

The discriminant b^2 - 4ac is < 0 for complex roots.

So we can choose appropriate values for a, b and c.

Let b = 1,  a = 1 and  c = 2 so b^2 - 4ac = 1 - 4*1*2 = -7.

So our equation is:

x^2 + x + 2 = 0.


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Which expression is equivalent to 7/2x -3(5x -1/2)
neonofarm [45]

Answer:

I think the answer is B, that was what i got

4 0
3 years ago
Let f(x)=3x^2+6x find f(2)<br><br>A.-4<br>B. 0<br>C. 4<br>D. 8
Anon25 [30]

Answer:

B maybe? that doesnt equal any

Step-by-step explanation:

f(x)=3x^2+6x

f(2)=3(2)^2+6(2)

f(2)=3(4)+12

f(2)=12+12

f(2)=24

7 0
3 years ago
SOMEONE PLEASE HELP!!!!!!!!!!!!!!!!!!1
UkoKoshka [18]

the answer is 5 if you need an explanation ask for it in the comments

8 0
3 years ago
Read 2 more answers
33. What is the value of x when x + 10 = 4?<br> A. -14<br> B. -6<br> C. O<br> D. 6
SCORPION-xisa [38]

Answer:

B. -6

Step-by-step explanation:

-6 + 10 =4

7 0
3 years ago
Read 2 more answers
How to solve -5y-y=1
goldenfox [79]
Since both y’s are negative you can combine them to make -6y=1 then you divide -6 on each Side to get y=6
5 0
3 years ago
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