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Sergio [31]
3 years ago
10

Determine the approximate measure of Y.

Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

I took the test, Its B) 41.1

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Dennis_Churaev [7]
7) (12 + 6)/(2 +4)
(18)/(6) = 3

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25 - 8 = 17

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60 - 5 x 5
60 - 25 = 35

11) 18 + (9/3) 
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hope this helps
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3 years ago
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Is k=6 a solution to the equation: 1/3k = 3
Step2247 [10]

Answer: No it's not

Step-by-step explanation:

1/3 x 6/1 = 6/3

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8 0
2 years ago
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From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng
alexandr402 [8]

Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

a. A point estimate of \mu and its 90% margin of error.

b. A 95% confidence interval for \mu.

Answer:

a

\= x  = 13.4   .   E = 2.3

b

10.7 <  \mu < 16.1

Step-by-step explanation:

From the question we are told that

  The sample size is  n = 18

  The 90% confidence interval is  (11.1, 15.7)

Generally the point estimate of  \mu is mathematically  evaluated  as

       \= x  = \frac{11.1 + 15.7 }{2}

=>    \= x  = 13.4

Generally the margin of error is mathematically evaluated  as

     E = \frac{15.7 - 11.1}{2 }

=> E = 2.3

  From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the equation for the lower limit of the confidence interval is  

      \= x  -  Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{18} } = 11.1

=> 13.4   -  0.3877 s  = 11.1

=>  s = 5.932

  From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =  1.96 *  \frac{5.932}{\sqrt{18} }

=>    E =  2.7      

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

=>    10.7 <  \mu < 16.1

3 0
3 years ago
A rocket was launched and its height, h, in metres, above the ground after time,
Marianna [84]
Short answer b 7m

Very simple just do the math mostly multiplying
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If a industrial machine made 678 shirts if you make 3 shirts in one minute how many minutes are you working
Aleks04 [339]
You simply divide 678 by 3 and get 226.
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