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3 years ago

Please help will give brainlyest

Mathematics

1 answer:

klio [65]3 years ago

4 0

Answer:

Step-by-step explanation:

Those are the first and last answers I can’t remember how to do the other two

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The school production of Our Town' was a big success. For opening night. 434 tickets were sold. Students paid $4.00 each, while

Alex73 [517]

Answer:

286 students attended

148 non students attended

Step-by-step explanation:

Given

$Tickets = 434$

$Students = \$4.00$

$Non-Students = \$6.00$

$Total = \$2032.00$

Solving (a): Number of students

Represent students with S and non students with N

So:

$S + N = 434$ --- (1)

$4S + 6N = 2032$ --- (2)

Make N the subject of formula in (1)

$N = 434 - S$

Substitute 434 - S for N in (2)

$4S +6(434 - S) = 2032$

Open Bracket

$4S + 2604 - 6S = 2032$

Collect Like Terms

$4S - 6S = 2032 - 2604$

$-2S = -572$

Divide through by -2

$S = 286$

<em>Hence; 286 students attended</em>

Solving (b):

Recall that

$N = 434 - S$

$N = 434 - 286$

$N = 148$

<em>148 non students attended</em>

4 0

2 years ago

If PQRS is a rhombus,which statement must be true? Check all that apply.

Oxana [17]

Answer: A, B, C, D

Step-by-step explanation:

A. This is true because all rhombi are parallelograms, and diagonals of a parallelogram bisect each other.

B. This is true because the diagonals of a rhombus are perpendicular.

C. This is true because diagonals of a rhombus bisect the angles from which they are drawn,

D. This is true because all sides of a rhombus are congfruent.

E. This is not always true - all rhombi are parallelograms, and adjacent angles of a parallelogram are supplementary, but not always congruent.

F. This is not always true - diagonals of a rhombus are not always congruent.

8 0

1 year ago

find the margin of error to use for this sample mean sushi based on a sample of 35 people he average out of pieces of sushi a pe

NNADVOKAT [17]

Answer:

{13.7756,18.2244}

Step-by-step explanation:

Given the sample size, the margin of error can be calculated with the formula $M=Z*\frac{\sigma}{\sqrt{n}}$ where Z is the critical value for the desired confidence level, σ is the population standard deviation, and n is the sample size. Therefore, our margin of error for a 90% confidence level is:

$M=Z*\frac{\sigma}{\sqrt{n}}=1.645*(\frac{8}{\sqrt{35}})=2.2244$

The formula for a confidence interval is $CI=\bar{x}+M$ where x-bar is the sample mean. Therefore, the 90% confidence interval for the mean amount of sushi pieces a person can eat is: