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3 years ago

PLZ HELP I DONT UNDERSTAND PLZ

Mathematics

1 answer:

MariettaO [177]3 years ago

8 0

I think the answer is (-1,-3)

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Angie and Kenny play online video games. Angie buys 1 software package and 3 months of game play. Kenny buys 1 software package

andrey2020 [161]

Answer:The cost of one month of game-play =$20

Step-by-step explanation:

Let the cost of one month of gameplay be x

Then cost of game-play bought by Angie =3x.....(1)

and Then cost of game-play bought by Kenny=4x......(2)

Cost of each software package =$50......(3)

The the total cost =240= sum of costs of software bought by both of them and game-play)=50+50+3x+4x

⇒240=100+7x.......→(by adding like terms)

⇒140=7x⇒x=20.....→( dividing both sides by 7 )

∴the cost of one month of game-play =$20

8 0

3 years ago

Read 2 more answers

What is the LCM for 9 and 12

Serhud [2]

36! goodluck hope it good

8 0

2 years ago

Help I do not understand

tamaranim1 [39]

$\bf \begin{cases}
f(x)=\cfrac{x}{x-9}
\\ \quad \\
g(x)=\cfrac{-x}{x-3}
\end{cases}\qquad f(x)+g(x)\implies \cfrac{x}{x-9}+\cfrac{-x}{x-3}$

get their LCD, like you'd with any other fractions, and add them up

5 0

3 years ago

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi

Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

$\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872$

From central limit theorem, we have:

$z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}$

where n is the sample size.

Here, n = 1 minute = 60 seconds

P(x > 950)

$P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)$

$= 1 - P(z \leq 1.667)$

Calculation the value from standard normal z table, we have,

$P(x > 950) = 1 - 0.952 = 0.048$

0.048 is the probability that more than 950 message arrive in one minute.

3 0

3 years ago

Two fair dice are rolled. Determine the following probability

VashaNatasha [74]

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8 0

2 years ago