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mamaluj [8]
3 years ago
13

A line passes through the point (2, 7) and has a slope of 4. What is the equation of the line?

Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0

Answer:

y=4x-1

Step-by-step explanation:

Remember the point slope form equation y-y1=m(x-x1) where m is the slope and the given point is (x1,y1)

y-7=4(x-2) . Plug in the numbers for the equation

y-7=4x-8   distributive property

y = 4x-1

Sergeeva-Olga [200]3 years ago
7 0
Y=4x-1 is the equation that passes through (2,7)

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Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

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3 0
3 years ago
Is 0.6 60 and 6 equal?
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Yesss

Step-by-step explanation:

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