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3 years ago

12

My family drinks an average of 3.4 gallons of milk every week 1 kept This Record over 5 weeks how many cups of milk did my famil

y drink while I was keeping recordes

1 answer:

DerKrebs [107]3 years ago

5 0

17 Gallons or.....272 Cups

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Please help me understand this

Delvig [45]

The correct answer is 75% increase.

The number 4 to 7 is increasing not decreasing since the number is higher than before.

Also 4 x 0.75 = 3 and 4 + 3 = 7 so it’s and increase of 75%

Hope this helps.

7 0

3 years ago

David proved the Law of Cosines with reference to ∆ABC using a different method. Arrange the steps of his proof in the correct s

irinina [24]

image of solution attached below

7 0

3 years ago

Help someone <br> Work and correct = brainlist

EastWind [94]

13.

<3 = 180 - <1

<3 = 180 - 90

<3 = 90°

14.

<8 = 180 - <6

<8 = 180 - 137

<8 = 43°

15.

<4 = 180 - <2

<4 = 180 - 34

<4 = 146°

5 0

3 years ago

22: A 2.0 kg object moves along the x-axis under the influence of an unknown force. Its potential energy due to the force is U(x

aleksandr82 [10.1K]

Answer: a) -13.25 N, b) 1.78 m/sec

Step-by-step explanation:

Since we have given that

$U(x)=ax^4+bx^2$

where

$a=2.5\ J/m^4\\\\b=12\ J/m^2$

As we know that

$F=\dfrac{-dU}{dx}=-(4ax^3+2bx)$

Here, x= 0.5 m

So, it becomes,

$F=-(4\times 2.5\times (0.5)^3+2\times 12\times 0.5)=-13.25\ N$

Now, we need to find the velocity when it crosses the origin,

$F=mg\\\\F=m\dfrac{dv}{dt}\\\\F=mv\dfrac{dv}{dx}\\\\-(4ax^3+2bx)dx=mvdv\\\\\int\limits^{0.5}_0 {-(4ax^3+2bx)} \, dx =\int\limits {mv} \, dv\\\\ \dfrac{-4ax^4}{4}+\dfrac{2bx^2}{2}|_0^{0.5}=\dfrac{mv^2}{2}\\\\ax^4+bx^2|_0^{0.5}=\dfrac{mv^2}{2}\\\\2.5(0.5)^4+12(0.5)^2=\dfrac{2v^2}{2}\\\\0.15625+3=v^2\\\\3.15625=v^2\\\\\sqrt{3.15625}=v\\\\v=1.78$

Hence, a) -13.25 N, b) 1.78 m/sec

7 0

4 years ago

A total of 612 tickets were sold for the school play. They were either adult tickets or student tickets. There were 62 more stud

Anuta_ua [19.1K]

Answer:

550

Step-by-step explanation:

It´s 550 because 612-62 is 550

8 0

3 years ago