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3 years ago

Find the first three terms of: 84-4n

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

6 0

Answer:

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Step-by-step explanation:

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Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr

dybincka [34]

Answer:

$\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}$

Step-by-step explanation:

$\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}$

The applicable rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a/b) = log(a) -log(b)

log(a^b) = b·log(a)

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3 years ago

Drew invests $70.00. It earns 50% interest annually.

VladimirAG [237]

Step-by-step explanation:

50% interest annually.

that means he gets 50% interest of the invested capital every year.

and that means he gets 50% of $70 in one year.

70 = 100%

1% = 100%/100 = 70/100 = $0.70

50% = 1%×50 = 0.7 × 50 = $35

he will earn $35 interest in one year.

as you noticed: 50% simply means 1/2 (as 100% stands for the whole).

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1 year ago

Find the slope and y-intercept of the graph of the equation.

kramer

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Simplify (-2)^3*(-2)^4

Otrada [13]

(-2)^3 x (-2)^4 = (-2)^7

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4 years ago

Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t

Viefleur [7K]

Each term differs by -68 and the first term is -68, we have:

$a_{n}=a_1-68(n-1) \implies \\ a_{n}=a_1-68n+68 \implies\\ a_n=-68-68n+68 \implies \\ a_n=-68n$

As an expession it's just -68n.

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3 years ago