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kupik [55]
3 years ago
14

What is the area of a sector with a central angle of 4π5 radians and a radius of 11 cm? Use 3.14 for π and round your final answ

er to the nearest hundredth. Enter your answer as a decimal in the box. 11 cm²
Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0

Answer:  151.98 cm²

<u>Step-by-step explanation:</u>

Area_{\ sector}=\dfrac{r^2}{2}\cdot \theta\\\\.\qquad \qquad =\dfrac{(11)^2}{2}\cdot \dfrac{4}{5}\pi\\\\.\qquad \qquad =\dfrac{242}{5}\pi\\\\.\qquad \qquad =151.976

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Evaluate how organizations can use one-sample hypothesis testing to determine if there are performance issues in the organizatio
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Answer:

Organizations can use one-sample hypothesis test to determine if there are performance issues in many ways.

It can be applied to the performance of a sector, a machine, a product, an advertising campaing, etc.

For example, we can take the example of a machine. It may be claimed that a specific machine performs significantly worse than the average.

This average would be the population mean: the average performance of the machines of the same type or process.

Then, a sample of the performance of the machine in study is taken and the hypothesis test can be performed to test the claim that this machine performs significantly worse.

Step-by-step explanation:

For example, we have an historic performance for this type of machine of 100 units a day. The machine A in study is sampled 14 days and have a performance of 92 units a day, with a sample standard deviation of 12 units/day. We have to test the claim that the machine A makes less units per day than the average.

Then, the null and alternative hypothesis are:

H_0: \mu=100\\\\H_a:\mu< 100

The significance level is 0.05.

The sample has a size n=14.

The sample mean is M=92.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{14}}=3.2071

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{92-100}{3.2071}=\dfrac{-8}{3.2071}=-2.4944

The degrees of freedom for this sample size are:

df=n-1=14-1=13

This test is a left-tailed test, with 13 degrees of freedom and t=-2.4944, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.0134) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that machine A produces significantly less units per day than the average.

3 0
3 years ago
Help me with this thanks for anyone who helps! :D
Kobotan [32]

Answer:

x= 90-60

x=30

Step-by-step explanation:

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2 years ago
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Answer:

C) P (X2 ≤ 8.2) = 0.96

Step-by-step explanation:

P value for the test is the probability of obtaining results that have been observed in the null hypothesis statement. A very small value of p indicates that there is unlikely chance of null hypothesis being true which means that we cannot accept null hypothesis based on the small p value.

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Cross multiplying we get
x^2 = 2*7x
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