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Aliun [14]
4 years ago
7

Calculate the ph of a 1.00 liter buffer solution that contains 0.300 m hc2h3o2 and 0.300 m nac2h3o2. (b) calculate the ph of thi

s solution after 0.020 mol of naoh is added (neglect any volume changes
Chemistry
1 answer:
Blababa [14]4 years ago
6 0

(a) 4.75; (b) 4.81

<h2>(a) pH of buffer</h2>

<em>Step 1.</em> Write the equation for the equilibrium

HC2H3O2 + H2O ⇌ C2H3O2^(-) + H3O^(+); pKa = 4.75

or

HA + H2O ⇌ A^(-) + H3O^(+)

<em>Step 2.</em> Calculate the pH of the buffer

The Henderson-Hasselbalch equation is

pH = pKa + log([A^(-)]/[HA]) .

pH = 4.75 + log((0.300 mol/L)/(0.300 mol/L)) = 4.75 + log1.00 = 4.75 + 0

= 4 .75

<h2 /><h2>(b) pH of buffer after adding NaOH</h2>

<em>Step 1.</em> Calculate the new concentrations of HA and A^(-)

We can use an ICE table for the calculation.

_______HA + H2O ⇌ H3O^(+) + A^(-)

I/mol:__0.300_______0.300

C/mol:_-0.020______+0.020

E/mol:__0.280_______0.320

pH = pKa + log([A^(-)]/[HA]) = 4.75 + log((0.320 mol/L)/(0.280 mol/L))

= 4.75 + log1.143 = 4.75 + 0.058 = 4 .81

This result makes sense because adding a base to a buffer should increase its pH.

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Design techniques and materials that reduce the negative environmental
Scrat [10]

Answer:

Green design

Explanation:

The word ‘Green’ represents designs which are eco friendly and less harmful to humans and other organisms. It helps in the protection of natural resources such as water, air etc.

Green Design are also referred to as techniques and materials that reduce the negative environmental impact of a structure.

3 0
4 years ago
How many moles of NaCl will react completely with 18.5 L F2 gas at 300.0 K and 1.00 atm?
meriva
Hello!

Data:

P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)

Apply the data to the Clapeyron equation (ideal gas equation), see:
P*V = n*R*T

1*18.5 = n*0.082*300

18.5 = 24.6n

24.6n = 18.5

n =  \dfrac{18.5}{24.6}

\boxed{\boxed{n \approx 0,752\:mol}}\end{array}}\qquad\checkmark

Note: If the feedback is to be considered, the closest response is 0.751 mol Nacl

_________________
_________________

I hope this helps. =)


3 0
4 years ago
In the laboratory, a student dilutes 13.5 mL of a 11.6 M hydroiodic acid solution to a total volume of 100.0 mL. What is the con
igomit [66]

Answer: The concentration of the diluted solution is 1.566M.

Explanation:

The dilution equation is presented as this: M_{s} V_{s} =M_{d} V_{d}.

·M= molarity (labeled as M)

·V= volume (labeled as L)

·s= stock solution (what you started with)

·d= diluted solution (what you have after)

Now that we know what each part of the formula symbolizes, we can plug in our data.

11.6M*13.5mL=M_{d} *100mL

We cannot leave it like this because the volumes must be in Liters, not milliliters. To convert this, we divide the milliliters by 1000.

13.5mL/1000=0.0135L     100mL/1000=0.1L

Now that we have the conversions, let's plug them into the equation.

11.6M*0.0135L=M_{d} *0.1L

The only thing that we need to do now is actually solving the answer.

M_{d} =\frac{11.6M*0.0135L}{0.1L}       M_{d} =1.566M

From the work shown above, the answer is 1.566M.

I hope this helps!! Pls mark brainliest :)

7 0
2 years ago
A mixture of helium and neon gases has a density of 0.6048 g/L at 48.7°C and 792 torr. What is the mole fraction of neon in this
weeeeeb [17]
The volume of one mole of gas is 22.4 liters at 0 °C and 760 Torr. The volume of the given condition can be calculated using:
(PV)/T = constant
(P₁V₁)/T₁ = (P₂V₂)/T₂
(760 * 22.4)/273 = (792 * V₂) / 321.7
V₂ = 25.3 Liters
The Mr of He = 4
The Mr of Ne = 20
Density of He = 4/25.3 = 0.1581 g/L
Density of Ne = 20/25.3 = 0.7905 g/L
Let x be the fraction of Ne
1 - x is the fraction of He
avg density = sum[(mole fraction * Mr)/V]
0.6048 = (20x + 4(1 - x))/25.3
x = 0.70
5 0
3 years ago
Determine whether a solution of the compound given will rotate light when subjected to polarimetry. Is a solution of compound A
kumpel [21]

Answer:

The question is incomplete. the compound wasn't attached to the question. Find attached of the compound and the answer too.

1. No

2. No

3. Yes

4. Yes

Explanation:

See the attached file for the answer.

7 0
3 years ago
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