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vazorg [7]
3 years ago
13

Determine whether a solution of the compound given will rotate light when subjected to polarimetry. Is a solution of compound A

optically active? yes no Is a solution of compound B optically active? yes no Is a solution of compound C optically active? yes no Is a solution of compound D optically active? yes no

Chemistry
1 answer:
kumpel [21]3 years ago
7 0

Answer:

The question is incomplete. the compound wasn't attached to the question. Find attached of the compound and the answer too.

1. No

2. No

3. Yes

4. Yes

Explanation:

See the attached file for the answer.

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Use the drop-down menu to complete the sentence.
Paha777 [63]

Answer:

It's called carbon dioxide.

Explanation:

CO_{2} consists of 1 carbon atom bonding with two oxygen atoms.

5 0
3 years ago
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The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq
Pavlova-9 [17]

Answer : The molarity of I_3^- in the solution is, 0.128 M

Explanation :

The given balanced chemical reaction is,

2S_2O_2^{-3}(aq)+I_3(aq)\rightarrow S_4O_2^{-6}(aq)+3I^-(aq)

First we have to calculate the moles of Na_2S_2O_3.

\text{Moles of }Na_2S_2O_3=\text{Molarity of }Na_2S_2O_3\times \text{Volume of solution}

\text{Moles of }Na_2S_2O_3=0.260mole/L\times 0.0296L=0.007696mole

Conversion used : (1 L = 1000 ml)

Now we have to calculate the moles of I_3^-.

From the balanced chemical reaction, we conclude that

As, 2 moles of S_2O_2^{-3} react with 1 mole of I_3^-

So, 0.007696 moles of S_2O_2^{-3} react with \frac{0.007696}{2}=0.003848 mole of I_3^-

The moles of I_3^- = 0.003848 mole

Now we have to calculate the molarity of I_3^-.

\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}

Now put all the given values in this formula, we get:

\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M

Therefore, the molarity of I_3^- in the solution is, 0.128 M

8 0
3 years ago
What is the concentration of a sodium hydroxide solution if 14.5 mL of it are exactly neutralized by 30.0 mL of a 0.500 M hydroc
rusak2 [61]

Answer:

1.03 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

30.0 mL (0.0300 L) of 0.500 M HCl react.

0.0300 L × 0.500 mol/L = 0.0150 mol

Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl

The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.

Step 4: Calculate the molar concentration of NaOH

0.0150 moles of NaOH are in 14.5 mL (0.0145 L).

M = 0.0150 mol/0.0145 L = 1.03 M

4 0
3 years ago
What is combustion in physics
NISA [10]
Combustion is a chemical reaction that occurs between a fuel and an oxidizing agent that produces energy, usually in the form of heat and light.
5 0
3 years ago
What is a chemical reaction???<br>koi<br>h​
Andru [333]

A chemical reaction is a process in which one or more substances referred to as reactants are converted into one or more substances referred to as products.

  • A chemical reaction can be defined as a chemical process that gives as a result one or more substances referred to as products of that reaction.

  • A chemical reaction is catalyzed by specific proteins called enzymes, which are capable of lowering the activation energy of a chemical reaction.

  • The most common types of chemical reactions include decomposition, synthesis, single and double replacement.

In conclusion, a chemical reaction is a process in which one or more substances referred to as reactants are converted into one or more substances referred to as products.

Learn more about chemical reactions here:

brainly.com/question/6876669

4 0
2 years ago
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