Answer:
CrO2
Explanation:
Firstly, we need to find the mass of the oxygen in the oxide. That is 4.94 - 3.06 = 1.88g
Now, we will need to get the number of moles and this can be obtained by dividing the masses by the atomic mass units. The atomic mass units of chromium and oxygen are 52 and 16 respectively. The division is obtained as follows:
Cr = 3.06/52 = 0.06
O = 1.88/16 = 0.12
We then divide by the smallest, which is that of the chromium.
Cr = 0.06/0.06 = 1
O = 0.12/0.06 = 2
The simplest formula is the empirical formula and it is thus given by CrO2
Answer:
3.97 M
Explanation:
Given data:
Initial volume V₁ = 318 mL
Initial molarity M₁ = 5.75 M
New volume V₂= 461 mL
New concentration M₂= ?
Solution:
New volume V₂= 143 mL+ 318 mL
New volume V₂= 461 mL
Formula:
M₁V₁ = M₂V₂
M₂ = M₁V₁ / V₂
M₂ = 5.75 M × 318 mL / 461 mL
M₂ = 1828.5 M. mL/ 461 mL
M₂ = 3.97 M
Is the equation wrong. Such a equation cannot be formed. pls enter the write equation i will help you
Answer:
B. It is a nonliving resource.
Explanation:
The definition of abiotic is "nonliving," and examples of abiotic resources may include soil or water.
THE ANSWER IS B. The reducing of oxidation state (-1 to -2, a change of -1, a REDUCTION) is what makes it a reduction.
