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Harlamova29_29 [7]

3 years ago

13

What precaution should be used when dealing with sulfuric acid in this experiment and why?

1 answer:

ryzh [129]3 years ago

4 0

Sulfuric acid is capable of hurting the skin, eyes, paper, metals, and even stone in some cases.

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kepler's first law explains that the sun is the focus of our solar system, and that _____. the orbit of a planet around the sun

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Name the following ionic compounds: (a) K2Cr2O7, (b) Li2C2O4, (c) CuNO3.

Elis [28]

Answer :

(a) The name of $K_2Cr_2O_7$ is, potassium dichromate.

(b) The name of $Li_2C_2O_4$ is, lithium oxalate.

(c) The name of $CuNO_3$ is, copper nitrate.

Explanation:

Ionic compound : It is a type of compound that is made up of the ions of the two different elements in which one element is a metal and another element is a non-metal.

(a) $K_2Cr_2O_7$

The given compound $K_2Cr_2O_7$ is an ionic compound. It is made up of two different ions which are potassium ion $(K^+)$ and dichromate ion $(Cr_2O_7^{2-})$ .

So, the name of $K_2Cr_2O_7$ is, potassium dichromate.

(b) $Li_2C_2O_4$

The given compound $Li_2C_2O_4$ is an ionic compound. It is made up of two different ions which are lithium ion $(Li^+)$ and oxalate ion $(C_2O_4^{2-})$ .

So, the name of $Li_2C_2O_4$ is, lithium oxalate.

(c) $CuNO_3$

The given compound $CuNO_3$ is an ionic compound. It is made up of two different ions which are copper ion $(Cu^+)$ and nitrate ion $(NO_3^{-})$ .

So, the name of $CuNO_3$ is, copper nitrate.

4 0

3 years ago

kupik [55]

Answer:

1. 0.82 gram of Ag+

2. 4.79 g of Ag₂O₃S

Explanation:

From the given information:

Total amount of Ag₂O₃S = 2.24 grams

Atomic mass of Ag+ =107.86 g/mole

molar mass of Ag₂O₃S = 295.8 g/mole

∴

The mass of the Silver (Ag) in grams is:

$= Total\ amount \ of \ Ag^+ \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}$

$=2.24 \times \dfrac{107.86 \ g/mol}{295.8 \ g/mol}$

= 0.82 gram of Ag+

2.

Here, the total amount of Ag₂O₃S = unknown

Atomic mass of Ag+ = 107.86 g/mole

molar mass of Ag₂O₃S = 295.8 g/mole

amount of Ag+ = 1.75 g

∴

The mass of Ag₂O₃S = $Total \ amount \ of \ Ag^+ \times \dfrac{295.8 \ g/mol}{107.86\ g/mol}$

$=1.75 \times \dfrac{295.8 \ g/mol}{107.86\ g/mol}$

= 4.79 g of Ag₂O₃S

4 0

3 years ago