G(x)= -x^2 as when you square a negative it has the same result as a positive
Step-by-step explanation:
by having two equations that have the same point, you can set the two equations equal to each other
y = 12x + 3, y = x + 1
12x + 3 = x + 1
11x = -2
x = -2/11
when you find the the x value, plug it back into either one of the equations
y = x + 1
y = (-2/11) + 1
y = 11/11 - 2/11
y = 9/11
the point (solution):
(-2/11, 9/11)
Answer:
-64.7999999983
Step-by-step explanation:
<h3>
Answers:</h3><h3>x = sqrt(10)</h3><h3>y = sqrt(5)</h3>
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Explanation:
Naturally I start with x as that letter precedes y in the alphabet; however, it's easier to start with y because it is a leg of this triangle. We will then use the value of y to find x later.
For any 45-45-90 triangle, the two legs are the same length. So that's why we're able to quickly see that y = sqrt(5)
To get the hypotenuse, we multiply the leg length by sqrt(2). This trick only works for 45-45-90 triangles.
hypotenuse = leg*sqrt(2)
x = sqrt(5)*sqrt(2)
x = sqrt(5*2)
x = sqrt(10)
The rule I used is sqrt(a)*sqrt(b) = sqrt(a*b)
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An alternate path is to use the pythagorean theorem to find x
a^2+b^2 = c^2
(sqrt(5))^2 + (sqrt(5))^2 = x^2
5 + 5 = x^2
10 = x^2
x^2 = 10
x = sqrt(10)
Answer:
Step-by-step explanation:
Unless we set x^2 + 8x + 15 equal to zero, we don't have an equation to be solved. I will assume that the problem is actually x^2 + 8x + 15 = 0.
The coefficients of this quadratic are {1, 8, 15}, and so the "discriminant" b^2 - 4ac is (8)^2 - 4(1)(15), or 4. Because the discriminant is positive, we know that there are two real, unequal roots.
Continuing with the quadratic formula and knowing that the discriminant is 4, we get:
-8 ± √4 -8 ± 2
x = ---------------- = --------------- , or x = -2 ± 1: x = -3 and x = -5
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