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3 years ago

A newsboy notices he has four times as many dimes as quarters. if his dimes and quarters total$1.95, how many of each has he?

1 answer:

4 0

D=4q
25q+10d=195
5q+2d=39

sub 4q foro d
5q+2(4q)=39
5q+8q=39
13q=39
divide 13
q=3

d=4q
d=4(3)
d=12

12 dimes
3 quarters

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Tina uses 50$ gift certificate to buy a pair of pajamas for 17.97, a necklace for 25.49, and 3 pairs of socks that each cost the

Gwar [14]

17.97 + 25.49 + 3x = 50.33
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3 years ago

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What is the value of a for the following circle in general form?<br> x2 + y² + ax + by+c=0

motikmotik

Answer:

Step-by-step explanation:

x2+y2+ax+by+c=0

Step 1: Add -by to both sides.

ax+by+x2+y2+c+−by=0+−by

ax+x2+y2+c=−by

Step 2: Add -x^2 to both sides.

ax+x2+y2+c+−x2=−by+−x2

ax+y2+c=−bax+y2+c+−y2=−by−x2+−y2

ax+c=−by−x2−y2

Step 4: Add -c to both sides.

ax+c+−c=−by−x2−y2+−c

ax=−by−x2−y2−c

Step 5: Divide both sides by x.

−by−x2−y2−c

y−x2

6 0

2 years ago

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Find the coordinates of the endpoint of the image?

ra1l [238]

Given:

The graph of a line segment.

The line segment AB translated by the following rule:

$(x,y)\to (x+4,y-3)$

To find:

The coordinates of the end points of the line segment A'B'.

Solution:

From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).

We have,

$(x,y)\to (x+4,y-3)$

Using this rule, we get

$A(-2,-3)\to A'(-2+4,-3-3)$

$A(-2,-3)\to A'(2,-6)$

Similarly,

$B(4,-1)\to B'(4+4,-1-3)$

$B(4,-1)\to B'(8,-4)$

Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).

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3 years ago

For the remaining three problems, write always, sometimes, or never. If it is always true, give the property or two examples. If

Oduvanchick [21]

$x+x=2x\\
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Always true.

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3 years ago

The given line passes through the points and (-4, -3) and (4, 1).

Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

(x2 , y2) is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

perpendicular line to this line is -1/m

- The point-slope of the equation is $y - y_{1}=m(x - x_{1})$

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line $m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}$

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

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3 years ago