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pentagon [3]
3 years ago
5

Consider this expression

Mathematics
2 answers:
Sloan [31]3 years ago
8 0

Answer:

\displaystyle \large{(x + 9)(x - 8)}

The value of a is 9 and b is -8

Step-by-step explanation:

\displaystyle  \large{(x + a)(x  + b) =  {x}^{2}  + (a + b)x + ab}

We need to find two numbers that add up or subtract off to 1.

Then we also use the same two numbers that multiply and get -72.

Let's see:-

  • 9 and -8 seem like correct values.

Because 9+(-8) is 9-8 = 1

And 9(-8) is -72.

Therefore:

\displaystyle \large{ {x}^{2}  + x - 72 = (x + 9)(x - 8)}

The value of a is 9 and the value of b is -8 according to form of (x+a)(x+b)

Bess [88]3 years ago
6 0

Answer:

(x + 9)(x - 8)

Step-by-step explanation:

x² + x - 72

Consider the factors of the constant term (- 72) which sum to give the coefficient of the x- term (+ 1)

The factors are + 9 and - 8 , since

9 × - 8 = - 72 and 9 - 8 = 1 , then

x² + x - 72 = (x + 9)(x - 8)

with a = 9 and b = - 8

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4 years ago
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Using a System to Break Even
andreev551 [17]

Answer: P^2 - 10p + 24 = 0

Step-by-step explanation:

Given that a company’s weekly revenue, in thousands, is modeled by the equation

R = -p2 + 14p,

where p is the price of the product it makes. The company is considering hiring an outside source to distribute its products, which will cost the company 4p + 24 thousand dollars per week.

If the company want to break even, the cost of hiring distributors will be equal to the revenue per week.

Therefore,

-P^2 + 14p = 4p + 24

Collect the like terms

-P^2 + 14p - 4p - 24 = 0

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Multiply all by minus sign

P^2 - 10p + 24 = 0

8 0
3 years ago
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AleksandrR [38]
I would say your answer is false because my mom works on houses and she never does this....

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5 0
4 years ago
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9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
4 years ago
Write an equation for the nth term of the geometric sequence -4, 8, -16...
monitta
Just keeping going with 16×-2=?×-2=?×-2 untill u get you your ninth nuber as well with tge 2 is a negative, so a a positive × a negative equal a negative and a negative × a negative equal
4 0
3 years ago
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