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3 years ago

867,000 rounded to the nearest hundred thousand

Mathematics

1 answer:

swat323 years ago

3 0

900,000 because it is rounded up because of how rounding works

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What is the slope of the line that passes through the points (5,-25) and (10, -15)

Salsk061 [2.6K]

<h2>Answer:</h2>

All you need to do is use the slope formula: y₂ - y₁/x₂ - x₁.

$\frac{-15 - (-25)}{10 - 5}\\\\\frac{10}{5} = 2$

Always simplify the fraction!

4 0

3 years ago

Someone PLEASE HELP ME!

Otrada [13]

<span>The graph will get flatter from –1 to 1.As you raise a proper fraction to higher even powers, you get smaller values, so the y-values get closer to the x-axis.The graph will get closer to the y-axis, or narrower.As you raise values greater than 1 (or less than –1) to higher even powers, you get larger values, so the graph increases at a faster rate.

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3 years ago

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Please help me

Ne4ueva [31]

Answer:Answer:I can't read or see it

Step-by-step explanation:Answer:I can't read or see it

8 0

3 years ago

1.What is the slope of line b?<br> a.1/2<br><br> b.2<br><br> c.-1/2

Triss [41]

The slope for this equation is A. 1/2

4 0

3 years ago

Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)

dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = $\int_a^b \delta\left|r^{\prime}(t)\right| d t$

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

$\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}$

Further simplifying;

$\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}$

Now, use integration to find the mass of the wire;

$\begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}$

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

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The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0

2 years ago