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2 years ago

Find each angle measure

Mathematics

1 answer:

Aloiza [94]2 years ago

4 0

It would surely be helpful if you let us know which angles to measure!

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Four less than the quantity of 8 times n

blsea [12.9K]

Answer: 8n-4

Step-by-step explanation: Should be the answer youre looking for

3 0

2 years ago

Read 2 more answers

1/5 divided by 2/5<br> 1/5 divided by 2/5

sergejj [24]

Answer:

1/5 / 2/5 = 0.5

Step-by-step explanation:

8 0

2 years ago

Heres 20p for whoever solves this

Leokris [45]

Answer:

i dont remember how to answer this so heres some info from the graph.

the y-intercept of the first equation is 8.

the y-intercept of the second equation is 18.

the equations cross at (10,4)

6 0

3 years ago

Consider a communication source that transmits packets containing digitized speech. After each transmission, the receiver sends

Greeley [361]

Answer:

The probability mass function is

$F(x) = [ \left \ 8 } \atop {x}} \right. ] * p^x * q^{n - x }$

Step-by-step explanation:

From the question we are told that

The maximum transmission time is $n = 8$

Generally the number of times a packet is transmitted follows a binomial distribution given that the the results of successive transmissions are independent of one another and that the probability of any particular transmission being successful is p

Generally the probability mass function is mathematically represented as

$F(x) = [ \left \ 8 } \atop {x}} \right. ] * p^x * q^{n - x }$

Here x can take values x = 0 , 1 , 2 , 3 , ... , 7

8 0

2 years ago

2) The number of streetlights in a town is growing linearly. Four months ago (n = 0) there were 130 lights. Now (n = 4) there ar

IRINA_888 [86]

Answer:

Step-by-step explanation:

Since the number of streetlights in a town is growing linearly, the street lights are increasing in arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

For n = 0, T0 = 130, therefore,

130 = a + (0 - 1)d

130 = a - d - - - - - - - - - -1

For n = 4, T4 = 154, therefore,

154 = a + (4 - 1)

154 = a + 3d - - - - - - - - - -2

Subtracting equation 2 from equation 1, it becomes

- 24 = - 4d

d = - 24/- 4 = 6

Substituting d = 6 into equation 1, it becomes

130 = a - 6

a = 130 + 6 = 136

a) The explicit formula for the number of lights in n months is

Tn = 136 + 6(n - 1)

b) The number of months that it will take to reach 200 lights is

200 = 136 + 6(n - 1)

200 - 136 = 6(n - 1)

64 = 6(n - 1)

6n - 6 = 64

6n = 64 + 6 = 70

n = 70/6 = 11.66

Approximately 12 months

3 0

3 years ago