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kipiarov [429]
3 years ago
9

Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?

Mathematics
2 answers:
Degger [83]3 years ago
8 0

The recursive formula a_n = a_{n-1}-6 can be used to generate the shown sequence

Step-by-step explanation:

Recursive formula is the formula that is used to generate the next term of a sequence using previous term.

The general form of arithmetic sequence's recursive formula is:

a_n = a_{n-1}+d

Given

5,-1,-7,-13,-19

Here

a_1 = 5\\a_2 = -1\\a_3 = -7

First of all we have to find the common difference of the sequence.

So,

d = a_2 -a_1 = -1-5 = -6\\d = a_3-a_2 = -7+1 = -6

Putting the value of d in the general recursive formula

a_n = a_{n-1}-6

Hence,

The recursive formula a_n = a_{n-1}-6 can be used to generate the shown sequence

Keywords: Sequence, arithmetic sequence

Learn more about arithmetic sequence at:

  • brainly.com/question/3375830
  • brainly.com/question/3398261

#LearnwithBrainly

Harman [31]3 years ago
5 0

Answer:

C: f(n + 1) = f(n) - 6

Step-by-step explanation:

f(1) = 5

f(2) = -1

f(3) = -7

f(1) - f(2) = 6

or:

f(2) = f(1) - 6

Re-written to:

f(n + 1) = f(n) - 6

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Contact [7]

Find the equation of the inverse.

y =  {2}^{x + 5}  - 6

we have

y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6

step 1

Exchange the variables

x for y and y for x

x=\{2\}^{\{y+5\}}-6

step 2

Isolate the variable y

(x+6)=2^{(y+5)}

apply log both sides

\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\  \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}

step 3

Let

f^{(-1)}(x)=y

therefore

the inverse function is

f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5

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A

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