How do I do any of this?!

First I will build the envelope. For this, I am using a rectangular piece of material 28m long and 12m wide. Out of this materia

RUDIKE [14]

Answer:

3.728 cm²

90

Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is $28 \times \frac{1}{12} = 2.33$ m and the width of the patches is $12 \times \frac{2}{15} = 1.6$ m.

Therefore, the area of the patches is (1.6 × 2.33) = 3.728 m² each. (Answer)

Now, the area of the rectangular piece of material is (28 × 12) = 336 m²

Hence, $\frac{336}{3.728} = 90.37$ ≈ 90 such patches can be made out of the whole material. (Answer)

3 0

2 years ago

If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution

FrozenT [24]

Answer:

Yes we can conclude.

Step-by-step explanation:

The sampling distribution of $\hat{p}$ can be approximated as a Normal Distribution only if:

np and nq are both equal to or greater than 10. i.e.

np ≥ 10
nq ≥ 10

Both of these conditions must be met in order to approximate the sampling distribution of $\hat{p}$ as Normal Distribution.

From the given data:

n = 50

p = 0.80

q = 1 - p = 1 - 0.80 = 0.20

np = 50(0.80) = 40

nq = 50(0.20) = 10

This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution

6 0

2 years ago

Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent. How many text messag

professor190 [17]

Given that Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent.

Kimora's cell phone bill for one month is $52.

We need to determine the number of text messages Kimora sent for one month.

Also, we need to write and equation and solve it.

<u>The equation:</u>

Let x denote the number of text messages Kimora sent for one month.

Thus, the equation is given by

$35+0.05x=52$

Therefore, the equation for the number of text messages Kimora sent for one month is $35+0.05x=52$

<u>Solving the equation:</u>

We need to solve the equation $35+0.05x=52$

Subtracting both sides of the equation by 35, we get;

$0.05x=17$

Dividing both sides of the equation by 0.05, we get;

$x=340$

Therefore, the number of messages sent is 340.

3 0

3 years ago

Brainliest and 30 points please help

kolbaska11 [484]

Answer:

22. Perimeter = 52 units

Area = 160 Square Units

23. Notation form : $2 \times 10^{5}$

Standard Form : 200000

Step-by-step explanation:

22.

The formula for perimeter is

P = 2 (length + Width )

= 2 ( 2x+3x+1)

= 2(5x+1)

The Formula for Area of a rectangle is

A= length x width

A= $2x \times (3x+1)$

A= $6x^2+2x$

Now we have to find the Perimeter and Area for x = 5

P = 2(5 x 5 +1)

P= 2(26)

P=52 units

A= 6 x 5 x 5 + 2 x 5

A= 150 + 10

A= 160 square units

23.

A. By using rule of exponents , we can determine that both the results will be same.

B.

Miriam's calculation

$\frac{2.8 \times 10^{9}}{1.4 \times 10^{4}}$

$\frac{2.8}{1.4} \times 10^{9-4}$

$2 \times 10^5$

Priya's calculation

$\frac{2.8 \times 10^{2}}{1.4 \times 10^{-3}}$

$\frac{2.8}{1.4} \times 10^{2-(-3)}$

$2 \times 10^5$

Standard notation

$2 \times 10^5 = 200000$

4 0

2 years ago

Tickets for a minor league baseball game for an adult and two children cost a total of $21 the adult ticket is three dollars mor

oksian1 [2.3K]

Answer:the cost of one child's ticket is $6

the cost of one adult ticket is $9

Step-by-step explanation:

Let x represent the cost of one child's ticket

Let y represent the cost of one adult ticket.

Tickets for a minor league baseball game for an adult and two children cost a total of $21. This means that

2x + y = 21 - - - - - - - - - - 1

The adult ticket is three dollars more than a child's ticket. This means that

y = x + 3

Substituting y = x + 3 into equation 1, it becomes

2x + x + 3 = 21

3x + 3 = 21

3x = 21 - 3 = 18

x = 18/3 = 6

y = x + 3 = 6 + 3

y = 9

6 0

3 years ago