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3 years ago

The diameter of moon is 2160 miles . a model has a scale of 1 in. : 150 mi. what is diameter of model?

Mathematics

1 answer:

IRISSAK [1]3 years ago

7 0

2,160/150 = 14.4
The diameter is 14.4 inches.

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Translate the points two left and six up <br> W(4,8)<br> X(3,-2)<br> Y(6,5)

Ivenika [448]

Answer:

W'(2, 14)
X'(1, 4)
Y'(4, 11)

Step-by-step explanation:

To translate 2 left, subtract 2 from every x-value.

To translate 6 up, add 6 to every y-value.

W' = W +(-2, 6) = (4-2, 8+6)

W' = (2, 14)

X' = X +(-2, 6) = (3-2, -2+6)

X' = (1, 4)

Y' = Y +(-2, 6) = (6-2, 5+6)

Y' = (4, 11)

3 0

2 years ago

What is another word used to state mantle

Anika [276]

Also called mantelshelf

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2 years ago

Narra situasiones de la vida rreal las cuales tienen la utilidad los numer9s enteros

Licemer1 [7]

Answer:

¿Podría explicar la pregunta con más detalle?

Step-by-step explanation:

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2 years ago

Can somebody please help me!!

Murrr4er [49]

Answer:

the answer is c

congruence can happen in any shape as long as all the angles and sides match up

Step-by-step explanation:

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2 years ago

Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a

NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

$P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

And then substitute the values in it then

$Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

Learn more about probability here

brainly.com/question/24756209

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7 0

1 year ago