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Triss [41]
3 years ago
9

Clifton ran 6 miles in 39 minutes. At this rate, how much time Clifton takes to run one mile?

Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Option C: Clifton takes 6 minutes and 30 seconds to run one mile.

Explanation:

Given that Clifton ran 6 miles in 39 minutes.

We need to determine the time it takes for Clifton to run one mile.

To determine the time that it takes for Clifton to run one mile, we shall divide 39 minutes by 6 miles.

Thus, we have,

\frac{39 \ minutes}{6 \ miles}=6.5 \ minutes

              =(6+0.5) \ minutes -------(1)

To convert 0.5 minutes to seconds, let us multiply the value by 60.

Thus, we have,

0.5 \times 60= 30 \ seconds

Thus, substituting in equation (1), we have,

(6+0.5) \ minutes= 6 \ minutes \ and \ 30 \ seconds

Therefore, it takes 6 minutes and 30 seconds for Clifton to run one mile.

Hence, Option C is the correct answer.

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Find the area of the circle whose diameter is 68 cm​
postnew [5]

Answer:

1156πcm²

Step-by-step explanation:

Diameter = 68cm

Therefore radius = 68 ÷ 2 = 34cm

Area of a circle = πr²

= π × 34cm × 34cm

= π × 1156cm

= 1156πcm²

NOTE: In case you're given the value of pi, substitute it into the formula to get your answer

4 0
3 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x^2+3x-8? 1.99 2.00
Sergio [31]

Answer:

1.39

Step-by-step explanation:

Given the quadratic equation :

2x^2+3x-8 = 0

We could apply the quadratic equation formula :

a = 2 ; b = 3, c = - 8

The formula is stated as :

-b±sqrt(b² - 4ac)/2a

To save computation tune, we could use a calculator :

The roots are : - 2.886 ; 1.386

The positive solution rounded to the nearest hundredth is : 1.39

3 0
3 years ago
Use the survey results to find the probability that a respondent has a​ pet, given that the respondent has had a pet.
Elena-2011 [213]

Answer:

Probability that the respondent has a pet given that the respondent has had a pet is  \frac{37}{81}  or 0.46.

Step-by-step explanation:

We are given the following results below;

37​% have a pet now and have had a pet.

63​% do not have a pet now.

81​% have had a pet.

19​% do not have a pet now and have never had a pet.

Let event B = respondent has a pet now

Now, Probability that the respondent has had a pet = P(A) = 0.81

Probability that the respondent has a pet now and has had a pet = P(A \bigcap B) = 0.37

So, Probability that the respondent has a pet given that the respondent has had a pet is given by = P(B/A)

<u>This conditional probability is solved as ;</u>

     P(B/A)  =  \frac{P(A \bigcap B)}{P(A)}

                 =  \frac{0.37}{0.81}  = 0.46.

3 0
3 years ago
Find the midpoint of line AB <br><br> A) (4.5, 4.5) <br> B) (1.5, 1.5)<br> C) (3,3)<br> D) (2,2)
cricket20 [7]

Answer:

B.  (1.5, 1.5).

Step-by-step explanation:

Point A has coordinates (-3, -3) and point B is (6, 6).

The mid point  is  ((-3+6)/2 , (-3+6)/2)

= (3/2 , 3/2)

= (1.5, 1.5)  (answer).

4 0
3 years ago
F(x) = 6x + 1, find f (4c + 2)
Anni [7]

Answer:  24c + 13

Step-by-step explanation:

f(x) = 6x + 1

(4c + 2)

f(4c + 2) = 6(4c + 2) + 1

f(4c + 2) = 24c + 13

8 0
3 years ago
Read 2 more answers
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