3 years ago

Question 3 and 5 please I rly need help

Mathematics

1 answer:

Ganezh [65]3 years ago

5 0

Answer:

3) 0.14

5) 2/5

Step-by-step explanation:

3) Ok, so, the equation for number 3 would be 2.24/16, which would be 0.14.

5) Reducing fractions is simplifying them, so divide 40 and 100 by 10 each, which gets 4/10. then, divide each by 2 to get 2/5, which is the most it could be reduced.

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A large washer has an outer radius of 10mm and a hole with a diameter of 14mm. What is the area of the top surface of the washer

choli [55]

<h2>Answer:</h2>

The area of the top surface of the washer is: 160.14 square mm.

<h2>Step-by-step explanation:</h2>

The top of the surface is in the shape of a annulus with a outer radius of 10 mm and a inner radius of 7 mm ( since the diameter of the hole is: 14 mm and we know that the radius is half of the diameter)

Now, we know that the area of the annulus region is given by:

$Area=\pi (R^2-r^2)$

where R is the outer radius and r is the inner radius.

Here we have:

$R=10\ mm\\\\and\\\\r=7\ mm$

Hence, we have:

$Area\ of\ top\ surface=\pi (10^2-7^2)\\\\i.e.\\\\Area\ of\ top\ surface=\pi (100-49)\\\\i.e.\\\\Area\ of\ top\ surface=\pi\cdot 51\\\\i.e.\\\\Area\ of\ top\ surface=160.14\ mm^2$