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dimulka [17.4K]
4 years ago
7

Given that measure of angle 6 is 1/8 of measure of angle 4. Find the measures of these two angles if a∥b .

Mathematics
1 answer:
weeeeeb [17]4 years ago
3 0

Answer:

\angle 4=160^{\circ}, \angle 6=20^{\circ}

Step-by-step explanation:

Consider the below figure attached with this question.

Given information: a∥b, \angle 6=\frac{1}{8}\angle 4.

a∥b              (Given)

\angle 6=\frac{1}{8}\angle 4    (Given)

Multiply both sides by 8.

8\angle 6=\angle 4      ...(1)

If a transversal line intersect two parallel lines then the same sided interior angles and are supplementary angles.

\angle 6+\angle 4=180              (Same sided interior angles)

\angle 6+8\angle 6=180            (Substitution)

9\angle 6=180

Divide both sides by 9.

\angle 6=20

The measure of angle 6 is 20 degree.

Substitute this value in equation (1).

8(20)=\angle 4

160=\angle 4

The measure of angle 4 is 160 degree.

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iragen [17]

Answer:

y = 5x - 14

Step-by-step explanation:

First point coordinates

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y₁

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Second point coordinates

x₂

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y₂

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Result

Slope (m)

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Your function

The entered points belong to an increasing, linear function.

Equation: y = 5x - 14.

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3 years ago
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AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
3 years ago
Wht is the substitution of x+y=9 and x=2y
Rama09 [41]
I hope this helps you



2y+y=9



3y=9



y=3


x=2y=2.3=6
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Answer:

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Step-by-step explanation:

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