<img src="https://tex.z-dn.net/?f=1%2F3%5E%7B2%7D%20%2B3%5Cfrac%7B8%7D%7B9%7D" id="TexFormula1" title="1/3^{2} +3\frac{8}{9}" al

Tamiku [17]

3 years ago

t="1/3^{2} +3\frac{8}{9}" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

HACTEHA [7]3 years ago

5 0

Answer:

I'm not sure

Step-by-step explanation:

I'm sorry..........

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Find the 90% confidence interval for the population standard deviation given the following.

lions [1.4K]

Answer:

b. 2.01 < σ < 2.81

Step-by-step explanation:

The 90% confidence interval for the population standard deviation is calculated as:

$\sqrt{\frac{(n-1)*s^{2} }{X^2_{\alpha/2 } } }$ < σ < $\sqrt{\frac{(n-1)*s^{2} }{X^2_{1-\alpha/2 } } }$

Where n is equal to 51, s is equal to 2.34, $\alpha$ is 10%, $X^{2} _{\alpha /2}$ is the value for the Chi squared distribution with n-1 degrees of freedom that has a probability of $\alpha /2$ in the right tail and $X^{2} _{1-\alpha /2}$ is the value for the Chi squared distribution with n-1 degrees of freedom that has a probability of $1-\alpha /2$ in the right tail.

So, replacing n by 51, s by 2.34, $X^{2} _{\alpha /2}$ by 67.50 and $X^{2} _{1-\alpha /2}$ by 34.76, we get that the The 90% confidence interval is equal to:

$\sqrt{\frac{(51-1)*2.34^{2} }{67.50} } }$ < σ < $\sqrt{\frac{(51-1)*2.34^{2} }{34.76} } }$