To find the next term in an arithmetic sequence, your best bet would be to use the formula N(x)= N(1) + (x-1)*d, where x stands for the term you want to find, N(1) stands for the first number in the sequence, and d stands for the common difference between the numbers.
First, lets see what we can plug in. We know the first term in the sequence (N(1)) is 11, we know that we want to find the 23rd number in the sequence (x), and by subtracting the 2nd term by the 1st term (14-11), the common difference (d) is 3. When we plug that all into our equation, it should end up looking something like this: N(23)= 11 + (23-1)*3.
Next, we can break down the equation to solve it step by step using PEMDAS. Parenthesis go first, so N(23)= 11 + (23-1)*3 becomes N(23)= 11 + (22)*3. We don't have any exponents, so we can skip the E. Next, we do multiplication and division from left to right, so N(23)= 11 + (22)*3 becomes N(23)= 11 + 66. Finally, we do addition and subtraction from left to right, getting us from N(23)= 11 + 66 to N(23)= 77, which means that the 23rd number in the sequence is 77!
Answer:
x=4
Step-by-step explanation:
4x-6 + 2x = 18
Combine like terms
6x -6 = 18
Add 6 to each side
6x-6+6 =18+6
6x = 24
Divide each side by 6
6x/6 = 24/6
x =4
The amount of the radioactive substance is 374.6 g
<h3>How to determine the amount of
radioactive substance?</h3>
The given parameters are:
- Initial, a = 424 mg
- Rate, r = 6%
- Time, t = 2 hours
The amount of the radioactive substance is calculated as:
A(t) = a(1 - r)^t
This gives
A(t) = 424 * (1 - 6%)^t
At 2 hours, we have:
A(2) = 424 * (1 - 6%)^2
Evaluate
A(2) = 374.6
Hence, the amount of the radioactive substance is 374.6 g
Read more about exponential functions at:
brainly.com/question/2456547
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Answer: I dont know
Step-by-step explanation:
I rlly dont know
