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Amiraneli [1.4K]
3 years ago
15

Base your answer to the following question on the diagram shown and the given information

Mathematics
1 answer:
erik [133]3 years ago
6 0

Answer:

  29°

Step-by-step explanation:

  ∠1 ≅ ∠8

  3x+25 = 4x -17

  42 = x . . . . . . . . . . add 17-3x

Now, we can find the measure of ∠1:

  m∠1 = 3(42) +25 = 151

Angle 2 is the supplement to this, so has measure ...

  m∠2 = 180° -151° = 29°

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What is the percentage 23 over 50
fredd [130]
23/50 is 0.46 so the percentage would be 46%
7 0
3 years ago
Read 2 more answers
I need this pls helpp
alexandr1967 [171]

Answer:

m∠7 = 63 degrees

m∠8 = 117 degrees

m∠9 = 63 degrees

Step-by-step explanation:

When two lines intersect at a point, then they formed 2 pairs of vertically opposite angles and 4 pairs of linear angles

  • The vertically opposite angles are equal in measures
  • The linear angles have a sum of 180°

In the given figure

∵ There are two lines intersected at a point

∴ The angle of measure 117° and ∠8 are vertically opposite angles

∴ ∠7 and ∠9 are vertically opposite angles

∴ The angle of measure 117° and ∠7 are linear angles

∵ The vertically opposite angles are equal in measures

∴ The angle of measure 117° and ∠8 are equal in measures

∴ m∠8 = 117°

∵ The sum of the measures of the linear angles is 180°

∴ m∠7 + 117° = 180°

→ Subtract 118 from both sides

∵ m∠7 + 117 - 117 = 180 - 117

∴ m∠7 = 63°

∵ m∠7 = m∠9 ⇒ proved up

∴ m∠9 = 63°

3 0
3 years ago
A baseball is hit with an initial upward velocity of 70 feet per second from a height of 4 feet above the ground. The equation h
Katyanochek1 [597]
To solve you need to set the equation equal to 6 (the height at which the player caught the ball.

6 = -16t^2 + 70t + 4

Next put the equation in standard form by subtracting 6 from both sides

-16t^2 + 70t - 2 = 0

This equation can be simplified by dividing by 2

-8t^2 + 35t - 1 = 0

This equation cannot be factored, but we can use the quadratic formula to find a value for x. Using the equation above we can find the values for a=-8, b = 35 and c = -1.

using the quadratic formula we can solve for x

-b +/- sqrt(b^2 - 4ac)
-------------------------------
       2a

The solutions are

0.03 and 4.35. as 0.03 seems an unrealistic time to hit and catch a baseball we would expect the time to be 4.35 seconds.
8 0
3 years ago
Simplify the expression -3y-(8y+1)
drek231 [11]
−3y−(8y+1)

Distribute the Negative Sign:

=−3y+−1(8y+1)

=−3y+−1(8y)+(−1)(1)

=−3y+−8y+−1

Combine Like Terms:

=−3y+−8y+−1

=(−3y+−8y)+(−1)

=−11y+−1

4 0
3 years ago
Please answer this question​
xz_007 [3.2K]

Let p(t) be the number attendees and t be the ticket price measured in units of 10s of rupees. When the price is t = 7 (i.e. Rs70), there were p(7) = 300 people in attendance.

For each unit increase in t (i.e. for each Rs10 increase in price), p(t) is expected to fall by 20, so that

p(t + 1) = p(t) - 20

Solve for p(t). Suppose t ≥ 7. By substitution,

p(t + 1) = (p(t - 1) - 20) - 20 = p(t - 1) - 2×20

p(t + 1) = (p(t - 2) - 20) - 2×20 = p(t - 2) - 3×20

p(t + 1) = (p(t - 3) - 20) - 3×20 = p(t - 3) - 4×20

and so on, down to

p(t + 1) = p(7) - (t - 6)×20 = 420 - 20t

or

p(t) = 420 - 20 (t - 1) = 440 - 20t

With t = price per ticket (Rs/ticket) and p(t) = number of attendees = number of tickets sold, it follows that the income made from ticket sales for some fixed ticket price t would be t×p(t). If one plots p(t) in the coordinate plane, the price that maximizes income and number of attendees is such that the area of a rectangle inscribed by the line p(t) and the coordinate axes is maximized.

Let A(t) be the area of this rectangle, so

A(t) = t p(t) = 440t - 20t²

Without using calculus, complete the square:

A(t) = 440t - 20t² = 2420 - 20 (t - 11)²

This is the equation of a parabola with vertex at (11, 2420), so the optiml ticket price is Rs11, and at this price the drama club can expect an income of Rs2420.

With calculus, differentiate A with respect to t and find the critical points:

A'(t) = 440 - 40t = 0   ⇒   11 - t = 0   ⇒   t = 11

Differentiate A again and check the sign of the second derivative at this critical point:

A''(t) = -40   ⇒   A''(11) = -40 < 0

which indicates a local maximum at t = 11 of A(11) = 2420.

6 0
2 years ago
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