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S_A_V [24]
3 years ago
5

12. What is the scale factor of a drawing ifthe scale is 1 inch = 4 feet?​

Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Answer:

if i was u i would either put g or h because there's no 48 in the word problem

Step-by-step explanation:

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Bella spent 15% of her paycheck at the mall, and 40% of that was spent at the
Bingel [31]

Answer:

$229

Step-by-step explanation:

Pay check = P

so

Total spent movie  T = $13.74

T = 0.4 *0.15* P = $13.74

The 40% on the Movie Theatre spending is part of the 15% spending at the mall.

So 40% of 15% of the Pay Check = $13.74

P = $13.74 / (0.4*0.15)  =  34.35/0.15 = 229

5 0
2 years ago
Read 2 more answers
2^5×5×11 and 2^3×5^2×7​
IceJOKER [234]

Answer:

1. 1760

2. 1400

Step-by-step explanation:

2^5 = 32

32 × 5 = 160

160 × 11 = 1760

2^3 = 8

5^2 = 25

8 × 25 = 200

200 × 7 = 1400

4 0
3 years ago
katie is baking cookies. the recipe calls for 3 eggs for every 2 cups of sugar. She will need 12 eggs.
asambeis [7]
She will need 8 cups because if u multiply 3 x 4 = 12 and multiply 2x 4 and that gives you 8
7 0
2 years ago
Find general solutions of the differential equation. Primes denote derivatives with respect to x.
zepelin [54]

Answer:

\mathbf{3x^2y^3+2xy^4=C}

Step-by-step explanation:

From the differential equation given:

6xy^3 +2y ^4 +(9x^2y^2+8xy^3) y' = 0

The equation above can be re-written as:

6xy^3 +2y^4 +(9x^2y^2+8xy^3)\dfrac{dy}{dx}=0

(6xy^3 +2y^4)dx +(9x^2y^2+8xy^3)dy=0

Let assume that if function M(x,y) and N(x,y) are continuous and have continuous first-order partial derivatives.

Then;

M(x,y) dx + N (x,y)dy = 0; this is exact in R if and only if:

\dfrac{{\partial M }}{{\partial y }}= \dfrac{\partial N}{\partial  x}}} \ \ \text{at each point of R}

relating with equation M(x,y)dx + N(x,y) dy = 0

Then;

M(x,y) = 6xy^3 +2y^4\  and \ N(x,y) = 9x^2 y^2 +8xy^3

So;

\dfrac{\partial M}{\partial y }= 18xy^3 +8y^3

       \dfrac{\partial N}{\partial y }

Let's Integrate \dfrac{\partial F}{\partial x}= M(x,y) with respect to x

Then;

F(x,y) = \int (6xy^3 +2y^4) \ dx

F(x,y) = 3x^2 y^3 +2xy^4 +g(y)

Now, we will have to differentiate the above equation with respect to y and set \dfrac{\partial F}{\partial x}= N(x,y); we have:

\dfrac{\partial F}{\partial y} = \dfrac{\partial}{\partial y } (3x^2y^3+2xy^4+g(y)) \\ \\ = 9x^2y^2 +8xy^3 +g'(y) \\ \\ 9x^2y^2 +8xy^3 +g'(y) =9x^2y^2 +8xy^3 \\ \\ g'(y) = 0  \\ \\ g(y) = C_1

Hence, F(x,y) = 3x^2y^3 +2xy^4 +g(y)  \\ \\ F(x,y) = 3x^2y^3 + 2xy^4 +C_1

Finally; the general solution to the equation is:

\mathbf{3x^2y^3+2xy^4=C}

5 0
2 years ago
510x10^8 in standard form please help quick
GenaCL600 [577]

Answer:

51,000,000,000

Step-by-step explanation:

the 10^8 usually determines how many 0's will be added to the right side of the number

thus-  510x10^8 = 51,000,000,000

6 0
3 years ago
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