Using the atomic weights, K = 39, O=16 so KO2= 39+32=71. So K=39/71= 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2= 9.76+8g=17.76.
1 mole of MgS = 24.3 + 32.1 = 56.4 g
35.1 g MgS x 1 mol / 56.4 g = 0.622 mol
M = 0.622 mol / 0.835 L = 0.745 mol/L
Answer:
4
Explanation:
the actual change in phase is 4 on the diagram
