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3 years ago

How can you demonstrate that a piece of chalk has mass?

1 answer:

8 0

You can demonstrate that a piece of chalk has mass by putting it on a pan scale. Pan scales determine mass in grams. Also if the mass feels like it has some weight to it (although not to be confused with weight, they are two different things!), it most likely has mass.
Hope this helps!!

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Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom transitions into n= 2 and emit

EleoNora [17]

Answer:

Explanation:

Using the Rydberg formula as:

$\frac {1}{\lambda}=R_H\times Z^2\times (\frac {1}{n_{1}^2}-\frac {1}{n_{2}^2})$

where,

λ is wavelength of photon

R = Rydberg's constant (1.097 × 10⁷ m⁻¹)

Z = atomic number of atom

n₁ is the initial final level and n₂ is the final energy level

For Hydrogen atom, Z= 1

n₂ = 2

Wavelength = 410.1 nm

Also,

1 nm = 10⁻⁹ m

So,

Wavelength = 410.1 × 10⁻⁹ m

Applying in the formula as:

$\frac {1}{410.1\times 10^{-9}}=1.097\times 10^7\times 1^2\times (\frac {1}{n_{1}^2}-\frac {1}{2^2})$

Solving for n₁ , we get

n₁ ≅ 1

3 0

4 years ago

Read 2 more answers

Which common mineral is most resistant to both chemical and mechanical weathering?

Xelga [282]

Quartz is the type of mineral used for both mechanical and chemical weathering

3 0

4 years ago

What are some ideas for a compound machine for my middle school invention science project that can be useful in people's daily l

Zanzabum

A toothbrush that has toothpaste in the middle so it comes preloaded. That way it is cleaner and uses more product than normal

4 0

4 years ago

How can the solubility of a solution be increased?

REY [17]

By increasing the temperature.

8 0

4 years ago

The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be

dybincka [34]

Answer:

132.17 g

Explanation:

The reaction given , in the question is -

CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of CS₂ .

since ,

Moles of CS₂ = given mass of CS₂ / Molecular weight of CS₂

Since ,

the Molecular weight of CS₂ = 76

Given , mass of CS₂ = 72.57 g

Moles of CS₂ = 72.57 / 76 = 0.95 mol

Since ,

The yield is 92.0 % .

Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

6 0

3 years ago