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Aleks04 [339]
4 years ago
14

Given the equilibrium reaction: 2 A (aq) + 3 B (aq) <— —> 2 C (aq) + D (aq) and equilibrium concentrations of [A] = 0.60M,

[B] = 0.30 M, [C] = 0.10 M and [D] = 0.50 M. The Kc value will be:
a. 1.9 c. 2.4 b. 0.15 d. 0.51
Chemistry
1 answer:
Alex787 [66]4 years ago
5 0
Given the equilibrium reaction: 2 A (aq) + 3 B (aq) <— —> 2 C (aq) + D (aq) and equilibrium concentrations of [A] = 0.60M, [B] = 0.30 M, [C] = 0.10 M and [D] = 0.50 M. The Kc value will be:
a. 1.9 c. 2.4 b. 0.15 d. 0.51





Answer . A
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At 25.0 °C the Henry's Law constant for sulfur hexafluoride (SP) gas in water is 2.4x 10 M/atm Calculate the mass in grams of SF
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass is m =  0.0349 \ g

Explanation:

From the question we are told that

   The Henry's Law constant is  k = 2.4 *10^{10} M/atm

   The volume of water is V = 525 \ ml = 0.525 \ L

   The partial pressure is  P =  1.90 \ atm

   The temperature is T  = 25 ^oC

Henry's  law is mathematically represented as

       C  = P * k

Where C is  the concentration of sulfur hexafluoride(SP)

substituting value

        C = 1.90 * 2.4*10^{-4}

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substituting value

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The mass of SP that dissolved is

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Where Z is the molar mass of SP which has a constant value of

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So

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