Question

A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.

Answer 1

We have to deal with the distance in more detail
If the turtle is 11 times faster than the snail, the amount of distance he will cover is 11 times more.
d/(360 - d) = 1/11
11d = 360 - d
12d = 360
d =  30  The Snail covers 30 meters. The turtle covers 11*30 = 330 meters.

Answers
Rate of snail = 30 meters / 40 minutes = 3/4 meter / minute
Rate of turtle = 330 meters / 40 minutes = 8.25 meters / minute.