Question

Please help I've been stuck on this for a while ​

Answer 1

Answer:

x=5,y=2,z=-1

Step-by-step explanation:

x+y+z=6 ........1

2x-y+3z=5 ..........2

3x+2z=13 ⇒3x=13+2z ⇒ x=(13-2z)/3

substitute for x in equation 1 and 2

13-2z/3+y+z=6 ⇒13/3 -2z/3+y+z=6 ⇒z/3+y=6-13/3

z/3+y=5/3  first equation

2(13-2z)/3-y+3z=5

26/3-4z/3-y+3z=5⇒5z/3-y=5-26/3⇒

5z/3-y=-11/3  second equation

z/3+y=5/3  first equation

eliminate y

5z/3-y+z/3+y=-11/3+5/3

6z/3=-6/3

z=-1

x=(13-2z)/3 ( find x, bu substitute z=-1)

x=(13+2)/3

x=15/3 ⇒ x=5

x+y+z=6

5+y-1=6

y=6+1-5

y=2