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Anarel [89]
3 years ago
9

ge\bold\red{{HELP}}" align="absmiddle" class="latex-formula">​
tap the picture

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
8 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Question : 1

weight of microbe in a test tube is 0.001 g,

weight of 456 such test tubes :

  • 456 \times 0.001

  • 456 \times  \dfrac{1}{1000}

  • \dfrac{456}{1000}

  • 0.456

weight of microbes in 456 such test tubes is :

  • 456 g

Question : 2

One crate weights 32.5 kg

the, 100 crates weight :

  • 32.5 \times 100

  • 3250 \: kg

Question : 3

3. Push ups in one day - 53

push ups in 10 days :

  • 53 \times 10

  • 530 \:  \: push \:  \: ups

Question : 4

1 metal ball weights 5727 kg,

so, 100 metal balls weight :

  • 100 \times 5727

  • 572700 \:  \: kg
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A metal worker has several 1-kilogram bars of a metal alloy that contain 23% copper and several 1-kilogram bars that contain 79%
astraxan [27]

Answer:

30 each of 23% bars and 18 each of 79% bars

Step-by-step explanation:

If x is the number of 1 kg 23% copper bars, and y is the number of 1 kg 79% copper bars, then:

x + y = 48

0.23x + 0.79y = 0.44(48)

Substituting and solving:

0.23x + 0.79(48-x) = 0.44(48)

0.23x + 37.92 - 0.79x = 21.12

16.8 = 0.56x

x = 30

y = 48 - x

y = 18

You need 30 each of 23% bars and 18 each of 79% bars.

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Answer:

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3 years ago
An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

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