All categories

3 years ago

Iterations question please help

Mathematics

1 answer:

nataly862011 [7]3 years ago

6 0

Answer:

option d

{ 4, 8 , 16 , 32 }

Step-by-step explanation:

Given in the question a function

f(x) = 2x

initial value $x_{0}$ =2

First iteration

f(2) = 2(2)

= 4

$x_{1}=4$

Second iteration

f(4) = 2(4)

= 8

$x_{2)=8$

Third iteration

f(8) = 2(8)

= 16

$x_{3)=16$

fourth iteration

f(8) = 2(16)

= 32

$x_{4}=32$

You might be interested in

cookies for a school fundraiser cost $3.75 per box. The total amount recieved from the cookie sale is $2718.75. How many boxes o

Cloud [144]

Answer:

725

Step-by-step explanation:

5 0

2 years ago

It cost $0.60 for a 12 ounce can of beans how much does it cost per ounce ?

BartSMP [9]

Answer:

0.05

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

It is estimated that, during the past year, 27% of all adults visited a therapist and 46% of all adults used non-prescription an

coldgirl [10]

Answer:

(a) The probability of an adult using non-prescription antidepressants given that he visited the therapist is 0.78.

(b) The probability of an adult visited the therapist given that he was using non-prescription antidepressants is 0.46.

Step-by-step explanation:

Conditional probability of an event X given that another event Y has already occurred is:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)}$

Let A = an adult visited the therapist and B = an used non-prescription antidepressants.

Given:

P (A) = 0.27

P (B) = 0.46

P (A ∩ B) = 0.21

(a)

Compute the probability that a randomly selected adult who visited a therapist during the past year also used non-prescription antidepressants as follows:

$P(B|A)=\frac{P(A\cap B)}{P(A)} =\frac{0.21}{0.27} =0.77778\approx0.78$

Thus, the probability of an adult using non-prescription antidepressants given that he visited the therapist is 0.78.

(b)

Compute the probability that a randomly selected adult visited a therapist during the past year, given that he or she used non-prescription antidepressants as follows:

$P(A|B)=\frac{P(A\cap B)}{P(B)} =\frac{0.21}{0.46} =0.4565\approx0.46$