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nikitadnepr [17]
2 years ago
14

NEED HELP PLEASE WHAT IS THE NUMBER IN THE QUESTION MARK

Mathematics
1 answer:
bekas [8.4K]2 years ago
6 0

Answer:

i thing it is 2,if i wrong so sorry

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She invited 150 friends. But she only had 5 activities for her friends and her party only lasted 4 hours. How much time will eac
DanielleElmas [232]

Answer:

19.20 seconds.

Step-by-step explanation:

Given:

She invited 150 friends.

But she only had 5 activities for her friends and her party only lasted 4 hours.

Question asked:

How much time will each friend get on each activity ?

Solution:

First of all convert 4 hours into seconds:-

1 hour = 3600 seconds

4 hours = 3600 \times 4 = 14400 seconds

<u>By unitary method:</u>

150 friends get time in 5 activities = 14400

1 friend get time in 5 activities = 14400 \div 150 = 96 seconds

That means <u>each friend get 96 seconds in all 5 activities.</u>

Each friend get time on each activity = ?

Each friend get time on 5 activities = 96

Each friend get time on 1 activity = 96 \div 5 = 19.20 seconds

Thus, each friend will get 19.20 seconds on each activity.

4 0
3 years ago
Fiona was playing a game. She started on space #8. The cards told her to move forward 12 spaces, back 10 spaces, back 1 space an
solong [7]

Answer:

B. Space 14

Step-by-step explanation:

8 + 12 = 20

20 - 10 = 10

10 - 1 = 9

9 + 5 = 14

So the answer is Space 14.

3 0
2 years ago
Read 2 more answers
Number 11 on my integrated geometry test
Mariulka [41]

Answer:

C. tan 48° = 16.3 / x

Step-by-step explanation:

With reference angle A

Tan A = BC / AC

Tan 48° = 16.3 / x

Hope it helps

3 0
3 years ago
Pls pls help with this. extra points. why would i use factoring to solve this quadratic equation?
anzhelika [568]

Answer: x =  

-1/6 -2

explanation:

I looked it up on Math

way

5 0
3 years ago
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g The tangent plane to z=f(x,y) at the point (1,2) is z=5x+2y−10. (a) Find fx(1,2) and fy(1,2). fx(1,2)= Number fy(1,2)= Number
murzikaleks [220]

Answer:

The values for Fx(1,2) and Fy(1,2) are 5 and 2 respectively.

Approximation at points (1.1,1.9) is 0.7

Step-by-step explanation:

Given:

Tangent plane to  a surface z=5x+2y-10 as the function at point (1,2)

To find :

f(x,y) at (1,2)

partial derivatives of function w.r.t. (x and y) and value of that function at given points.

Solution:(refer the attachment also)

Now we know that

the equation of tangent plane at given points to the surface is given by,

f(x1,y1,z1) and z=f(x,y)

z-z1=Fx(x1,y1)*(x-x1)+Fy(x1,y1)*(y-y1)

here Fx(x1,y1) and Fy(x1,y1) are the partial derivatives of x and y.

now

taking partial derivative w.r.t. x we get

Fx(x1`,y1)=\frac{d}{dx} (5x+2y-10)

=5.

Then w.r.t y we get

Fy(x1,y1)=

\frac{d}{dy}(5x+2y-10)

=2.

The values for Fx(1,2) and Fy(1,2) are 5 and 2 respectively.

Using the Linearization or linear approximation we get

L(x,y)=f(x1,y1)+Fx(x,y)*(x-x1)+Fy(x,y)(y-y1)

=-1+5(x-1)+2(y-2)

=5x+2y-10

Approximation at F(1.1,1.9)

=5(1.1)+2(1.9)-10

=5.5+3.8-10

=0.7

Approximation at points (1.1,1.9) is 0.7

6 0
3 years ago
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