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nikitadnepr [17]
2 years ago
14

NEED HELP PLEASE WHAT IS THE NUMBER IN THE QUESTION MARK

Mathematics
1 answer:
bekas [8.4K]2 years ago
6 0

Answer:

i thing it is 2,if i wrong so sorry

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What's the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B33%20%5Ctimes%203%20%2B%201%7D%20" id
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I believe it’s 10

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For #6 the answer is 0.079.

For # 7 the answer is 200,000

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Step-by-step explanation:

dont forget to mark brainliest

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3 years ago
Involving the use of variables, properties, expressions, and equations
ankoles [38]
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Hope this answer is helpful


Please mark me as brainliest
7 0
3 years ago
a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


5 0
3 years ago
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