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nikitadnepr [17]
3 years ago
14

NEED HELP PLEASE WHAT IS THE NUMBER IN THE QUESTION MARK

Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

i thing it is 2,if i wrong so sorry

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N
MariettaO [177]

Answer:

0.7969

Step-by-step explanation:

Given that: A sample of size n= 49 is obtained. The population mean  is m= 80 and the population standard deviation is s = 14.

The z score measures the number of standard deviation by which the raw sore is above or below the mean. It is given by the equation:

z=\frac{x-m}{\frac{s}{\sqrt{n} } }

For x = 78.3, the z score is:

z=\frac{x-m}{\frac{s}{\sqrt{n} } }=\frac{78.3-80}{\frac{14}{\sqrt{49} } } =-0.85

For x = 85.1, the z score is:

z=\frac{x-m}{\frac{s}{\sqrt{n} } }=\frac{85.1-80}{\frac{14}{\sqrt{49} } } =2.55

P(78.3<x<85.1) = P(-0.85<z<2.55) = P(z<2.55) - P(z<-0.85) = 0.9946 - 0.1977 = 0.7969

7 0
4 years ago
Read 2 more answers
I need help with this
Marina CMI [18]
Yea I’m not sure more info?
6 0
3 years ago
A plane has an airspeed of 111 km/h. It is flying on a bearing of 79 degrees while there is a 25 km/h wind out of the northeast​
qwelly [4]

Answer: Ground Speed = 91 km/hr,   Bearing = 189°

<u>Step-by-step explanation:</u>

Step 1: Draw a picture (see attached) to determine the angle between the given vectors.  Notice that I moved the wind vector 180° <em>so the head of the wind vector would line up with the tail of the plane vector. </em>This created an angle of 34° between the plane and wind vectors. <em>Why?</em>

  • the dashed line is 45°
  • 79° (plane) - 45° (wind) = 34°

Step 2: Solve for the length of the resultant vector using Law of Cosines

<em>c² = a² + b² - ab cos C</em>

c² = (111)² + (25)² - (111)(25) cos 34°

c² = 12,946 - 4601

c² = 8345

c = 91

Ground speed is 91 km/hr

Step 3: Solve for the bearing of the resultant vector using Law of Sines

\dfrac{sin\ A}{a}=\dfrac{sin\ C}{c}

\dfrac{sin\ A}{25}=\dfrac{sin\ 34}{91}

sin\ A=\dfrac{25\ sin\ 34}{91}

A=sin^{-1}\bigg(\dfrac{25\ sin\ 34}{91}\bigg)

A = 9°

<em>Reminder that we moved the wind vector 180° to create the resultant vector so we need to add 180° to our answer.</em>

Bearing = A + 180°

              =  9° + 180°

              = 189°


7 0
3 years ago
You bought a freezer that is 2 geet wide, 4 feet long and 30 inches deep. What is the capacity or volume of the freezer?
inna [77]
34,560 cubic inches I think,
2ft= 24in
4ft= 48in
30in x 24in x 48in = 34,560
8 0
3 years ago
Read 2 more answers
34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
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