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Zepler [3.9K]
3 years ago
12

0 .17 as a fraction​

Mathematics
1 answer:
valentina_108 [34]3 years ago
7 0
0.17 as a fraction would be 17/100
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Find the following of each arc measure
Dimas [21]
ZW= 108
VW= 55
UY= 34
8 0
3 years ago
What number is it? the difference of 9 and three times equals 69. find the number
Mazyrski [523]
Consider the number as 'n' (for now)
3n - 9 = 69
3n = 69 + 9
3n = 78
n = 78/3
n = 26
Therefore, The number is 26
8 0
3 years ago
Kaitlin, Tony, and Austin sent a total of 103 text messages over their cell phones during the weekend. Austin sent 4 times as ma
emmainna [20.7K]

The number of messages Kaitlyn, Tony and Austin sent are 13, 18 and 72 messages respectively.

<h3>How to write and solve equation?</h3>

let

  • Number of messages Kaitlyn sent = x
  • Number of messages Tony sent = x + 5
  • Number of messages Austin sent = 4(x + 5)
  • Total messages = 103

103 = x + (x + 5) + 4(x + 5)

103 = x + x + 5 + 4x + 20

103 = 6x + 25

103 - 25 = 6x

78 = 6x

x = 78/6

x = 13

Number of messages each sent:

Number of messages Kaitlyn sent = x

= 13 messages

Number of messages Tony sent = x + 5

= 13 + 5

= 18 messages

Number of messages Austin sent = 4(x + 5)

= 4(13 + 5)

= 4(18)

= 72 messages

Learn more about equation:

brainly.com/question/2972832

#SPJ1

3 0
2 years ago
Which statement compares the two numbers correctly?
slamgirl [31]

Answer:

Step-by-step explanation:

So, we have-

(6 x .1) + (3 x .01) + (2  x .001)

So, we will solve inside of the parenthesis first.

6 x .1  = <u>.6</u>

So, we got that settled next-

3 x .01 = <u>.03</u>

We got that settled last-

2 x .001 = <u>.002</u>

Lastly, we add them all.

.6 + .03 + .002 =  .632

Now we compare.

.632 > .629

So, there is your answer!

Hope this helps!

7 0
2 years ago
involving the election of officers on a committee. Assume that the committee consists of 14 members including Tasha. The same th
Yanka [14]

Answer:

There are 364 ways of filling the offices.

Step-by-step explanation:

In this case, the order of filling of the offices does not matter, so, we can figure out the different ways of filling the offices by using the combination formula:

C^{n} _{r}=\frac{n!}{(n-r)!r!}

where n=14 (number of members)

r=3 number of offices

n!=n·(n-1)·(n-2)·...·3·2·1

C^{14} _{3}=\frac{14!}{(14-3)!3!}=\frac{14*13*12*11*10*9*8*7*6*5*4*3*2*1}{(11*10*9*8*7*6*5*4*3*2*1)*(3*2*1)}=\frac{14*13*12}{3*2*1} =364

5 0
3 years ago
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