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3 years ago

Equations and inequalities

2 answers:

8 0

Inequalities and equations use similar steps to solve, but inequalities give a range of numbers that can represent the variable while an equation will give a direct answer.

Example:

4+5x=24

First you would subtract 4 or add the opposite of 4 from 24.

4+5x=24
+(-4) +(-4)
—————
5x=20

Then divide each side by 5 or multiply each side by the reciprocal of 5 to isolate the variable.

1/5*5x=20*1/5 (reciprocal)
X= 4

You would use the same steps in an inequality but end up with a different sign.

Svetllana [295]3 years ago

5 0

Someone already answered so

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The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

Answer:

a) $P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b) $P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c) $P(A') = 1-P(A) =1-0.4=0.6$

d) $P(A \cup B) =0.4 +0.8-0.2 =1.0$

e) The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

a. P(A)

$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

Using the total law of probability we got:

$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

For this case $P(A \cap B) = P(c) =0.2$ , so if we replace we got:

$P(A \cup B) =0.4 +0.8-0.2 =1.0$

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

8 0

3 years ago

Find the source area of the space figure represented by the net

sergejj [24]

I assume you meant "surface area" :)

Looking at the net, it looks like if you folded it back together it would form to become a triangular prism.

To calculate the surface area of a triangular prism, you would use the formula: A = bh + 2ls + lb, where b is the base of the triangular faces, h is the height of the prism, l is the length of the prism, and s is the side length of the prism.

I attached a picture to help you see what these labels are.

Looking at the diagram you've provided, we can assume that b = 7 cm, h = 4 cm, l = 8 cm, and s = 5 cm. Substitute these into the formula.

A = bh + 2ls + lb ==> A = (7)(4) + 2(8)(5) + (8)(7)

Multiply from left to right.

28 + 80 + 56

Add.

164

The surface area of this triangular prism is A) 164 cm^2.

6 0

4 years ago

Help❗️Anybody know how to do this stuff?

Lunna [17]

I wish I did I would help u out but I hope u have luck

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4 years ago

What is the slope and y-intercept for y= -1

lianna [129]

Quick Answer.
<span>To solve the slope of 3x + 2y = 8, the equation must first be put into slope intercept form with y on the left side and the remaining numbers on the right side. It can be transformed to 2y = -3x + 8, which will then be simplified down to y = -3/2x + 8. The slope of the line is </span>-3/2<span>.</span>

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Dennis surveyed 30 students to determine their favorite fall sports. Of the students surveyed, 15 preferred football, 6 preferre

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Are the options to choose from? That is what it seems like.

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4 years ago

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