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3 years ago

PLEASE HELP! I WILL MARK YOU AS BRAINLIEST!

Mathematics

2 answers:

aleksklad [387]3 years ago

7 0

22/7x5x5( formula is pie x r2)

110/7 x5

550/7 (divide it)

78.571

2 DEC=78.570

steposvetlana [31]3 years ago

4 0

39.28 cm square

area of semi circle=(π×r^2)/2

radius=5cm

so (π×5^2)/2=78.55/2=39.275 which is gonna be in nearest 2 decimal is 39.28

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Crossword Puzzle

Vikki [24]

Answer:

Please read the answers below that solve the crossword puzzle about linear equations. Tested and proved offline!

Step-by-step explanation:

Across:

2. V a r i a b l e

9. S o l v e

10. S u b t r a c t i o n p r o p e r t y (Two words)

Down:

1. M u l t i p l i c a t i o n p r o p e r t y (Two words)

3. A d d i t i o n p r o p e r t y (Two words)

4. L i n e a r

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3 0

3 years ago

Read 2 more answers

Julie and Jan’s brother also withdrew money from his savings account on Monday. He made three withdrawals and withdrew $10 more

Zepler [3.9K]

Answer:

possible amounts could be $35, $55, $75

hope this helps!

Step-by-step explanation:

8 0

3 years ago

Find the domain of each function: g(x)= 1/x−9

defon

Answer:

x ∈ R, x ≠ 9

Step-by-step explanation:

Given

f(x) = $\frac{1}{x-9}$

The denominator of f(x) cannot be zero as this would make f(x) undefined.

To find the value that x cannot be, equate the denominator to zero and solve for x

x - 9 = 0 ⇒ x = 9 ← excluded value

Thus the domain is x ∈ R, x ≠ 9

4 0

3 years ago

What one is it?? Because I am having a hard time figuring it out. If anyone could help it would mean a lot, thanks

hichkok12 [17]

Answer:

the first one

Step-by-step explanation:

5 0

3 years ago

A test of sobriety involves measuring the subject's motor skills. Twenty randomly selected sober subjects take the test and prod

elena55 [62]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: motor skills of a sober subject.

n= 20

X[bar]= 37.1

S= 3.7

The claim is that the average score for all sober subjects is equal to 35.0, symbolically: μ= 35.0

The hypotheses are:

H₀: μ = 35.0

H₁: μ ≠ 35.0

α: 0.01

The statistic to use, assuming all conditions are met, is a one sample t- test

$t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

$t_{H_0}= \frac{37.1-35.0}{\frac{3.7}{\sqrt{20} } } = 2.34$

This test is two-tailed, meaning, the rejection region is divided in two and you'll reject the null hypothesis to low values of t or to high values of t:

$t_{n-1;\alpha /2}= t_{19; 0.005}=-2.861$

$t_{n-1;1-\alpha /2}= t_{19; 0.995}= 2.861$

The decision rule using this approach is:

If $t_{H_0}$ ≤ -2.861 or if $t_{H_0}$ ≥ 2.861, you reject the null hypothesis.

If -2.861 < $t_{H_0}$ < 2.861, you do not reject the null hypothesis.

The value is within the non rejection region, the decision is to not reject the null hypothesis.

I hope this helps!

3 0

3 years ago