How many ATP's are required to start glycolysis anf how many ATP's are produced?

Problems. Please calculate and/or hypothesize answers to the following questi problems. You may use another sheet of paper. 1. A

daser333 [38]

hope thhis helps! i have the answer in there and eveything is explained.

8 0

3 years ago

Vaccines prevent disease bya. bringing bacteria to infect healthy cells.

Veronika [31]

The correct answer is option d.

A vaccine refers to a biological preparation, which offers active acquired immunity to a specific disorder. A vaccine usually comprises an agent, which signifies a disease-causing microbe and is usually made from killed forms or attenuated microbe, one of its surface proteins, or from its toxins.

The agent instigates the immune system of the body to determine the agent as a danger, destruct it, and to further destroy and identify any of the microbes related with that agent, which it may come across in the coming future.

8 0

3 years ago

It says 15+ but it is 29 points

kozerog [31]

Answer:

I don't understand but the 15 is 15×2 = 29

6 0

3 years ago

Please help me with this I’m so confused!

prisoha [69]

Hello there!

One reason to why scientist would be able to know and learn to use this genetic code would be because they could totally use this purpose for other purposes. They could use it perhaps making electricity more economic. They could use this code in many different matters. They could possibly use it to make light at night without any batteries or any sort if electricity. This would be ways they could use this kind of tool.

I hope this helps you! <span />

8 0

3 years ago

In cucumbers, dull fruit (D) is dominant over glossy (d) fruit, orange friut (R) is dominant over cream fruit (r), and bitter co

stiv31 [10]

Explanation:

Dull fruit (D) is dominant over glossy (d) fruit.
Orange friut (R) is dominant over cream fruit (r).
Bitter cotyledon (B) is dominant over non-bitter cotyledons (b).

The three genes are independent.

A plant homozygous for dull, orange fruit and bitter cotyledons has the genotype <em>DDRRBB</em><em>.</em>
A plant homozygous for glossy, cream fruit and non-bitter cotyledons has the genotype <em>ddrrbb</em>.

100% of the F1 will have dull, orange fruit and bitter cotyledons and will be heterozygous for all genes: <em>DdRrBb</em>.

<u>The F2 will have 8 possible phenotypes:</u>

27 D_R_B dull, orange fruit and bitter cotyledons
9 D_R_bb dull, orange fruit and non-bitter cotyledons
9 D_rrB_ dull, cream fruit and bitter cotyledons
3 D_rrbb dull, cream fruit and non-bitter cotyledons
9 ddR_B_ glossy, orange fruit and bitter cotyledons
3 ddR_bb glossy, orange fruit and non-bitter cotyledons
3 ddrrB_ glossy, cream fruit and bitter cotyledons
1 ddrrbb glossy, cream fruit and non-bitter cotyledons

An F1 plant is crossed with a plant that has glossy, cream fruit and non-bitter cotyledons.

<h3>DdRrBb x ddrrbb </h3>

The F1 individual can produce 8 types of gametes: DRB, DRb, DrB, Drb, dRB, dRb, drB and drb. The cream fruit and non-bitter cotyledons individual can only produce drb gametes. This cross also produces a progeny with the following genotypes and phenotypic proportions:

8 DdRrBb dull, orange fruit and bitter cotyledons
8 DdRrbb dull, orange fruit and non-bitter cotyledons
8 DdrrBb dull, cream fruit and bitter cotyledons
8 Ddrrbb dull, cream fruit and non-bitter cotyledons
8 ddRrBb glossy, orange fruit and bitter cotyledons
8 ddRrbb glossy, orange fruit and non-bitter cotyledons
8 ddrrBb glossy, cream fruit and bitter cotyledons
8 ddrrbb glossy, cream fruit and non-bitter cotyledons

4 0

3 years ago