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3 years ago

Write an inequality comparing -6 and -3

Mathematics

2 answers:

olga2289 [7]3 years ago

7 0

-3+-6=n ..... So... N =?

CaHeK987 [17]3 years ago

5 0

Write an inequality comparing -6 and -3

Answer: -6 < -3

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Which number has the least value? 1. 2 3/4 2. 5/2 3. 2.62 4. 245%

Leni [432]

The number with the least value is 2.62

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3 years ago

Plz help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

iren2701 [21]

Answer:

88 inches

Step-by-step explanation:

The given bicycle has a tyre that is 28 inches in diameter.

How far the bicycle moves forward each time the wheel goes around is the circumference of the bicycle tyre.

This is calculated using the formula:

C =\pi \: d

We substitute the diameter and

\pi = \frac{22}{7}

C = \frac{22}{7} \times 28

This simplifies to

C =22 \times 4

88 \: inches

7 0

3 years ago

a warehouse holds 460 boxes. They ship out 65 boxes each week. After how many weeks will the warehouse have less than 100 boxes

Kamila [148]

It should take 6 weeks until the warehouse has less than 100 boxes remaining

6 0

2 years ago

Read 2 more answers

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

Practice isolating the variable to solve equations with

bulgar [2K]

Answer:

9 =6x

Step-by-step explanation:

We know this is the answer because the -4x was cancelled out left to the equal sign, and 2x has now become 6x after adding 4x.

5 0

3 years ago