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3 years ago

50 points help asap!

Mathematics

2 answers:

Luden [163]3 years ago

8 0

Answer:

58 feet.

Step-by-step explanation

Since the angle given is across from the length we need to find and we are given the hypotenuse, we use sine.

Sin(46)=x/80 where x is the height of the triangle and 80 is the hypotenuse.

80sin(46)=x

x=57.55 or 58 feet.

Fantom [35]3 years ago

4 0

AB=Perpendicular=80ft
Angle of elevation= $\theta$ =46°

We need Base i e BC

$\\ \rm\Rrightarrow tan46=\dfrac{AB}{BC}$

$\\ \rm\Rrightarrow BC=\dfrac{AB}{tan46}$

$\\ \rm\Rrightarrow BC=\dfrac{80}{1}\approx 80ft$

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klemol [59]

Answer:

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Step-by-step explanation:

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4 years ago

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sergey [27]

Answer:

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Step-by-step explanation:

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3 years ago

I need help with #65 to #70 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP… it is

never [62]

All of the given questions(#65 to #70) are AP(s).

Formula to be used: a(n) = a(1) + (n - 1)d

Pronounced as:

nth term = 1st term + (n - 1)d, where d is the common difference.

*d = difference of any two consecutive terms.

65):

1st term = 2, d = 6 - 2 = 4

Therefore,

11th term = 2 + (11 - 1)4 = 42

66):

1st term = 5, d = 15 - 5 = 10

Therefore,

16th term = 5 + (16 - 1)10 = 155

67):

1st term = 19, d = 39 - 19 = 20

Therefore,

21st term = 19 + (21 - 1)20 = 419

68):

1st term = 8, d = 38 - 8 = 30

Therefore,

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69):

1st term = 1/2, d = 1 - 1/2 = 1/2

Therefore,

101st term = 1/2 + (101 - 1)1/2 = 101/2

70):

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8 0

3 years ago

Solve this equation for x. Round your answer to the nearest hundredth. 0.77 = log x

Alekssandra [29.7K]

Answer:

x ≈ 5.89

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Algebra II

Exponential to Logarithmic: $\displaystyle b^m=x \rightarrow log_bx=m$

Step-by-step explanation:

Step 1: Define

Identify

0.77 = log(x)

Step 2: Solve for x

[Equality Property] Raise both sides to the 10th power: $\displaysytle 10^{0.77} = 10^{logx}$
Simplify: $\displaysytle x = 10^{0.77}$
Evaluate: $\displaysytle x = 5.88844$

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3 years ago