That's a quadratic, a nice parabola in vertex form.
The parabola has a positive x^2 term, so it's a CUP, concave up positive. It will have a minimum at the vertex, which is (2,5). Plot that point.
Now we need a couple of guide points to draw the usual parabola going up from both sides of its vertex. We try x=0 giving (0,9) and see that x=4 also gives 9, (4,9). Plot the parabola through those two points and the vertex and you're done.
Answer:
SAS
Step-by-step explanation:
Please let me know if this doesn't help. I'm trying my best to relearn this so I can help you.
(3y + 7) + (5y-7)= 8y
(4y - 5)- 8y= -4y-5
It would be x + y + 64
You subtract the -x from the 2x
