Answer:
A circle can intersect a parabola in
1. One point [ when circle just touches the parabola]
2. Two points [ When circle cuts the parabola in two distinct points. ]
3. Three points [Circle just touches at one point and cuts the parabola in two distinct points]
4. Four points [ Either parabola or circle meeting each other or crossing at four distinct points]
To solve this problem, we must substitute in 1 for the variable x in the equation. This is because the function as written is f(x), meaning that the function is evaluated as x currently, but we want to evaluate it at 1. To do this, all we have to do is replace each variable x with a 1 and simplify.
f(x) = x^2 + 2x + 3
f(1) = (1)^2 + 2(1) + 3
To simplify, we first to compute the exponents. This is because of the order of operations, which says that we should solve parentheses first, exponents next, then multiplication/division, then addition/subtraction last.
f(1) = 1 + 2(1) + 3
Next, as outlined above, we should perform the multiplication.
f(1) = 1 + 2 + 3
Finally, we can finish solving by adding together the remaining terms.
f(1) = 6
Therefore, your answer is 6.
Hope this helps!
The general form of radical expression is :
![y^n=\sqrt[n]{x}](https://tex.z-dn.net/?f=y%5En%3D%5Csqrt%5Bn%5D%7Bx%7D)
For the given expression:
Simplify :
![y^{\frac{3}{8}}=\sqrt[8]{y^3}](https://tex.z-dn.net/?f=y%5E%7B%5Cfrac%7B3%7D%7B8%7D%7D%3D%5Csqrt%5B8%5D%7By%5E3%7D)
Answer :
