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SSSSS [86.1K]
3 years ago
10

Given the following exponential function, identify whether the change represents

Mathematics
1 answer:
rewona [7]3 years ago
6 0

For the given exponential function, the change represents a growth  and the percentage rate is 0.3%.

<h3>Exponential Function</h3>

The formula for the exponential function is:

y(t)=y(0)*(1+R)^t, where:

y(t)= final value

yo=initial value

R=rate

t= time

When 1+R  > 1, the equation represents growth, while 1+R < 1 the equation represents decay.

The question gives:  y=30*(1.003)^x.

When you compare y=30*(1.003)^xwith y(t)=y(0)*(1+R)^t, it is possible to see:

1. 1+R=1.003, so >1 . Therefore, the change represents growth.

2. 1+R=1.003 , therefore,

                           1.003=1+R

                          R=1.003-1

                          R=0.003

                          then,

                       

                         %R=0.003*100=0.3%

                         

Read more about the exponential function here:

brainly.com/question/8935549

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200=300=100 it will stay the same so
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Find the surface area of the prism.<br><br><br><br>The surface area is square millimeters.​
asambeis [7]

Answer:

57.1mm^2

Step-by-step explanation:

4*4=16

16/2=8mm^2 cross section

(4*3) + (4*3) + (5.7*3) = 41.1mm

8*2=16

41.1+16=57.1mm^2

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3 years ago
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What is the determinant of the coefficient matrix of the system
vovikov84 [41]

The coefficient matrix is

\begin{bmatrix}-1&-1&2\\3&2&-1\\4&4&-8\end{bmatrix}

Its determinant is then

\det\begin{bmatrix}-1&-1&2\\3&2&-1\\4&4&-8\end{bmatrix}=-4\det\begin{bmatrix}-1&-1&2\\3&2&-1\\-1&-1&2\end{bmatrix}

which is equal to 0.

8 0
3 years ago
The first term of a geometric sequence is 6 and the fourth term is 384. What is the sum of the first 10 terms of the correspondi
aleksandrvk [35]

Answer:

2097150

Step-by-step explanation:

<u>GIVEN :-</u>

  • First term of G.P. = 6
  • Forth term of G.P. = 384

<u>TO FIND :-</u>

  • Sum of first 10 terms of the G.P.

<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>

<em>Geometric Progression :-</em>

  • It's a sequence in which the successive terms have same ratio.
  • General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]
  • Sum of 'n' terms of a G.P. ⇒ \frac{a(r^n - 1)}{r-1}.

<em>[NOTE :- </em>\frac{a(1-r^n)}{1-r} can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator &  denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>

<u>SOLUTION :-</u>

Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.

⇒ a = 6

It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-

=> ar^3 = 384

=> 6r^3 = 384

Divide both the sides by 6.

=> \frac{6r^3}{6} = \frac{384}{6}

=> r^3 = 64

=> r = \sqrt[3]{64} = 4

Sum of first 10 terms = \frac{6(4^{10}-1)}{4 - 1}

                                     = \frac{6(1048576 - 1)}{3}

                                     = 2 \times 1048575

                                     = 2097150

6 0
3 years ago
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