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SSSSS [86.1K]
2 years ago
10

Given the following exponential function, identify whether the change represents

Mathematics
1 answer:
rewona [7]2 years ago
6 0

For the given exponential function, the change represents a growth  and the percentage rate is 0.3%.

<h3>Exponential Function</h3>

The formula for the exponential function is:

y(t)=y(0)*(1+R)^t, where:

y(t)= final value

yo=initial value

R=rate

t= time

When 1+R  > 1, the equation represents growth, while 1+R < 1 the equation represents decay.

The question gives:  y=30*(1.003)^x.

When you compare y=30*(1.003)^xwith y(t)=y(0)*(1+R)^t, it is possible to see:

1. 1+R=1.003, so >1 . Therefore, the change represents growth.

2. 1+R=1.003 , therefore,

                           1.003=1+R

                          R=1.003-1

                          R=0.003

                          then,

                       

                         %R=0.003*100=0.3%

                         

Read more about the exponential function here:

brainly.com/question/8935549

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A circular pool with a diameter of 18 ft will have a uniform 4 ft concrete walkway poured around it. If the concrete cost $4.25 a square foot, how much will it cost for the concrete?

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Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

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(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

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