Answer:
The rate of change of the distance between the cars at that instant is 5.46 meters per second
Step-by-step explanation:
Speed of first car = 7 m/s
Speed of second car = 3 m/s
At instant, distance of first car from intersection = 5 meters
distance of second car from intersection = 12 meters
Therefore, we have
Distance between both cars at intant = √(12² + 5²) = 13 m
Rate of cahnge of distance is given by;
2ddd/dt = d(x² + y²)/dt = 2xdx/dt + 2ydy/dt
= 26dd/dt = 2×5×7 + 2×12×3 = 142
dd/dt = 142/26 = 5.46 m/s.
That is the rate of change of the distance between the cars at that instant = 5.46 meters per second.
There is no solution because when you distribute the 6 on the right side you get
6x+18
So the equation is
6x-9=6x+18
This is unsolvable because x must be the same on both sides, so there are no solutions
F(X)=13 Just Plug 10 into the X in the equation
Answer:
Step-by-step explanation:
distribute 3√7 by multiplying to each term In parenthesis
3√7×2√2+3√7×4√7
6√14+12√49
6√14+12(7)
6√14+84
