3 years ago

What is a whole number between the square root of 27 and the square root of 39

1 answer:

8 0

That number would be 6.
Since 5^2 = 25 and 6^2 = 36, we can see that the only possible whole number between sqrt(27) and sqrt(39) has to be 6.

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Lawrence drives the same distance monday through Friday commuting to and from work. Last week Lawrence drove 25 miles on the wee

alexira [117]

Answer:

60 - 25 = 35

35 / 7 = 5

Lawrence drives 5 miles each day commuting to and from work.

8 0

3 years ago

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If the quadrilateral below is a kite, find m

Debora [2.8K]

Answer:

49°

Step-by-step explanation:

7.5x-15+90=180

7.5x+75 =180

7.5x=105

x =14

so NPQ = ( 4×14 -7 ) = 49° this the answer

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2 years ago

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Three times a number is no less than negative six.

tresset_1 [31]

the equation for the stated problem would be:

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3 years ago

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The standard form of the equation of a circle is (x−5)2+(y−6)2=1.

Crank

Answer:

(A) $x^2+y^2-10x-12y+60=0$

Step-by-step explanation:

The standard form of the equation of a circle is given as:

$(x-5)^2+(y-6)^2=1$

Simplifying the above given equation, we get

$x^2+25-10x+y^2+36-12y=1$

$x^2+y^2-10x-12y+36+25=1$

$x^2+y^2-10x-12y+61=1$

$x^2+y^2-10x-12y+60=0$

which is the required general form of the equation.

Hence, option A is correct.

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3 years ago

Find the product.<br><br> (−x−3)(2x2+5x+8)=

harina [27]

$( - x - 3)(2 {x}^{2} + 5x + 8) = \\ = - 2 {x}^{3} - 5 {x}^{2} - 8x - 6 {x}^{2} - 15x - 24 = \\ = - 2 {x}^{3} - 11 {x}^{2} - 23x - 24$

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3 years ago