Answer:
The perimeter of the quarter-circle is 200 cm.
Step-by-step explanation:
Given that the angle of quarter-circle is 90°. So using Length of Arc formula, you are able to find the length of curve :
Let r be radius = 56 cm,
Let θ = 90°
We have already found the arc. Next we have to add up together to find the perimeter :
Answer:
x=48
y=70
step by step explanation:
In the question,
<em>Si</em><em>nce</em><em> </em><em>the</em><em> </em><em>trian</em><em>gle</em><em> </em><em>two</em><em> </em><em>sides</em><em> of</em><em> the</em><em> </em><em>traingl</em><em>e</em><em> </em><em>is</em><em> </em><em>equal</em><em>,</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>isosc</em><em>eles</em><em> </em><em>triangle</em><em>.</em>
<em>For</em><em> </em><em>an</em><em> </em><em>isosc</em><em>eles</em><em> triangle</em><em>,</em><em> </em><em>angles </em><em>oppos</em><em>ite</em><em> </em><em>to</em><em> </em><em>eq</em><em>ual</em><em> </em><em>sides</em><em> </em><em>are</em><em> </em><em>equal</em><em>,</em>
<em>Hence</em><em>,</em>
Hi there!
a. Find the displacement by plugging in the values of the interval:
f(2) - f(0) = 0 - 2 = -2 meters.
Average velocity is the slope, thus:
The average velocity for the interval is -1 m/s.
b. To find the speed at the endpoints, we must take the derivative to get the velocity equation:
f(t) = t² - 3t +2
f'(t) = 2t - 3, at t = 0, speed = |-3| = 3 m/s. At t = 2, speed = 2(2) - 3 = 1 m/s.
Acceleration is the second derivative, thus:
f''(t) = 2. The acceleration is 2 m/s² for both endpoints.
c. When the body changes direction, the first derivative changes signs. Thus:
0 = 2t - 3
3 = 2t, t = 1.5 sec. This is where the body changes direction.