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3 years ago

How do you write 3/4 as percentage?

Mathematics

2 answers:

kotegsom [21]3 years ago

7 0

The answer to your question is 75%

german3 years ago

5 0

3/4 is 75%

for this think of them as quarters 4 quarters is 100 %, 2 quarters is 50% so 3 quarters would be 75%

or you could just do 3 divided by 4 then times that by 100

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Solve the following system: y=1 y=-6x-5

Mandarinka [93]

Answer:

x = -1

y = 1

Step-by-step explanation:

Since it gives you "y", plug in the number given into the equation:

y = -6x - 5

1 = -6x - 5

Then, add 5 to both sides:

1 = -6x - 5

+5 + 5

________

6 = -6x

Divide both sides by -6:

6 = -6x

-1 = x

So now you have, x = -1 and y = 1

4 0

3 years ago

Read 2 more answers

Write two decimals that can be rounded to 1.5

evablogger [386]

It can be either 1.4 or 1.3 or your looking to your nearest 5th

5 0

2 years ago

Read 2 more answers

For the data set 7, 10, 10, 14, 14, 17, the mean is 12. What is the mean

anastassius [24]

Answer: The mean absolute devastation is 3

Step-by-step explanation:

4 0

2 years ago

Find the probability that when a couple has children, at least one of them is a . (Assume that boys and girls are equally lik

lora16 [44]

Answer:

$P(At\ least\ one\ girl) = 0.875$

Step-by-step explanation:

Given

$n = 3$

$B \to boys$

$G \to girls$

$P(G) = P(B) = 0.5$ --- equal probability

See comment for complete question

Required:

$P(At\ least\ one\ girl)$

To do this, we make use of complement rule:

$P(At\ least\ one\ girl) = 1 - P(No\ girl)$

The event that there is no girl out of the 3 children is: B B B

And the probability is:

$P(No\ Girl) = P(B) * P(B) * P(B)$

$P(No\ Girl) = 0.5*0.5*0.5$

$P(No\ Girl) = 0.125$

So:

$P(At\ least\ one\ girl) = 1 - P(No\ girl)$

$P(At\ least\ one\ girl) = 1 - 0.125$

$P(At\ least\ one\ girl) = 0.875$

4 0

3 years ago

Find the area of semi-circle whose radius is 'm' units.

Sav [38]

Radius of the circle = m units
Therefore, area of the circle $= \pi \: {m}^{2} square \: \: units$
We know, semi-circle is half of a circle.
So, the area of the semi-circle $= \frac{\pi \: {m}^{2} }{2} \: square\: \: units$

Answer:

$\frac{\pi \: {m}^{2} }{2} \: square\: \: units$

Hope you could understand.

If you have any query, feel free to ask.

7 0

2 years ago